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Andre45 [30]
3 years ago
12

Jonas has a 10.0 kg box, which he places on a scale inside an elevator. When the

Physics
1 answer:
Gennadij [26K]3 years ago
3 0

Answer:

a = - 1.47 [m/s²], descending or going down

Explanation:

To solve this problem we must use Newton's second law which tells us that the sum of forces on a body is equal to the product of mass by acceleration.

∑F = m*a

where:

∑F =  Forces applied [N]

m = mass = 10 [kg]

a = acceleration [m/s²]

Let's assume the direction of the upward forces as positive, just as if the movement of the box is upward the acceleration will be positive.

By performing a summation of forces on the vertical axis we obtain all the required forces and other magnitudes to be determined.

-m*g + N = m*a\\

where:

g = gravity acceleration = 9.81 [m/s²]

N = normal force measured by the scale = 83.4 [N]

Now replacing:

-(10*9.81)+83.4=10*a\\-14.7=10*a\\a=-1.47[m/s^{2} ]

The acceleration has a negative sign, this means that the elevator is descending at that very moment.

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b) 6 \Omega, 1.33 A

Explanation:

a)

In this situation, we have two resistors connected in series.

The equivalent resistance of resistors in series is equal to the sum of the individual resistances, so in this circuit:

R=R_1+R_2

where

R_1=4\Omega

R_2=1 \Omega

Therefore, the equivalent resistance is

R=4+1=5 \Omega

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I=\frac{V}{R}

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I=\frac{8}{5}=1.6 A

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b)

In this part, a third resistor is added in series to the circuit; so the new equivalent resistance of the circuit is

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Substituting, we find the equivalent resistance:

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