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3 years ago

10

A particle is launched at an angle of 37° from horizontal. If the horizontal velocity component is 7.65 meters/second, what is t

he resultant velocity of the particle?

1 answer:

larisa [96]3 years ago

3 0

Answer:

R = 9.58 m/s

Explanation:

cos(37) = (7.65 m/s)/R

R = (7.65 m/s)/cos(37)

R = 9.58 m/s

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Answer:

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Explanation:

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emmasim [6.3K]

Answer:

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Approximately, Angular acceleration =

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Explanation:

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There is an equation that shows us the relationship between Torque and Angular acceleration.

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Angular acceleration = Torque ÷ Inertia

Where:

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Where M = Mass

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Angular Acceleration =

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what is the maximum speed of a 34-g object bouncing on a spring (k=78.1 N/m) with an amplitude of 3.5-cm?

Vika [28.1K]

Answer:

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