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Leto [7]
3 years ago
14

Which of the following is an elastic collision?

Physics
2 answers:
UNO [17]3 years ago
6 0
I think its B. Two cars colliding and sticking together.or C. A wad of gum sticking to a window.
fiasKO [112]3 years ago
3 0
D is also an example
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Which is one use for radioactive isotopes? sanitation architecture meteorology archaeology
e-lub [12.9K]

Answer:

Archaeology

Explanation:

Radioisotopes are radioactive atoms of an element in which their atoms contain excess energy making them unstable. When broken down they become more stable releasing radiations.

Carbon 14 is a radioactive isotope that is used in archaeology to study and estimate the lifespan and age of organic materials such as wood, leather. Carbon 14 can be used to estimate the ages of materials up to 50000 to 60000 years.

7 0
3 years ago
A motor cycle travelling at 10 m/s accelerates at 4m/s(squared) for 8s.
Sever21 [200]


10 x 4^2 = 160 / 8..

V = 20m/s...

...x 8 = 100 miles,meters, metric what ever m stands for after 8 seconds.

This is my guess since the problem says 4m/s^2

V= distance/ ST (traveled/used)
8 0
2 years ago
A frog hops 5m east and 2m north. What is the magnitude of the frogs total displacement in m?
TiliK225 [7]

As per the question a frog jumps 5 m towards east.

Frog again jumps 2 m north.

Let the displacement along east is denoted by vector A and the displacement towards north is denoted as vector B.

Hence magnitude of A = 5 m

           Magnitude of B = 2 m

We are asked to calculate the total displacement.

Here the angle between them is 90 degree as A is towards east and B is towards north.

As per parallelogram law of vector addition,the magnitude of total displacement [R] will be-

                            R=\sqrt{ A^{2} +B^{2}+2AB\cos\theta}

                            =\sqrt{ 5^{2}+ 2^{2}+2*5*2 cos 90}

                            =\sqrt{25+4+0} m  [cos90= 0]

                            =\sqrt{29} m

                            = 5.38516 m   [ans]

                     


7 0
3 years ago
g A motorist traveling at 30.0 m/s passes a stationary police car. The police car gives chase 2.0 s later, accelerating at 5.0 m
Sedaia [141]

The time for the police car to catch up with the speeding motorist is 7.6 seconds.

<h3>What time will the police car catch up with the speeding motorist?</h3>

The police car and the motorist will cover equal distances.

Let the distance covered be d.

Distance covered by the motorist  = speed * time

time = t, speed = 30 m/s

d = 30t

Distance covered by the police car = acceleration * (time)

time = t - 2, acceleration = 5.0 m/s²

d = 5(t-2)²

d = 5(t² - 4t + 4)

d = 5t² - 20t + 20

Equating the two equations for distance

5t² - 20t + 20 = 30t

5t² - 50t + 20 = 0

Solving for t using the quadratic formula:

t = 9.6 second or 0.4 seconds

Since t > 2, t = 9.6 seconds

t - 2 = 9.6 - 2

t - 2 = 7.6 seconds

Therefore, the time for the police car to catch up with the speeding motorist is 7.6 seconds.

Learn more about distance and acceleration at: brainly.com/question/14344386

#SPJ1

4 0
1 year ago
Q: What happens when cold air approaches a body of warm air?     Optional Answers:      A. The Warm air rises.     B. The warm a
artcher [175]
A. The warm air rises! Hope this helps
8 0
3 years ago
Read 2 more answers
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