To answer this
problem, we use the binomial distribution formula for probability:
P (x) = [n!
/ (n-x)! x!] p^x q^(n-x)
Where,
n = the
total number of test questions = 10
<span>x = the
total number of test questions to pass = >6</span>
p =
probability of success = 0.5
q =
probability of failure = 0.5
Given the
formula, let us calculate for the probabilities that the student will get at
least 6 correct questions by guessing.
P (6) = [10!
/ (4)! 6!] (0.5)^6 0.5^(4) = 0.205078
P (7) = [10!
/ (3)! 7!] (0.5)^7 0.5^(3) = 0.117188
P (8) = [10!
/ (2)! 8!] (0.5)^8 0.5^(2) = 0.043945
P (9) = [10!
/ (1)! 9!] (0.5)^9 0.5^(1) = 0.009766
P (10) = [10!
/ (0)! 10!] (0.5)^10 0.5^(0) = 0.000977
Total
Probability = 0.376953 = 0.38 = 38%
<span>There is a
38% chance the student will pass.</span>
Answer:
30
Step-by-step explanation:
27 diviend by 9 = 3 so 27 +3 = 30.
In the two triangles, all the three sides are congruent to the corresponding sides of the other triangle. And in such case, the criteria used for congruency is Side Side Side or SSS .
So the correct option is the first option .
The domain and range is all real numbers.
<h3>Answer: D) Domain: (-∞, ∞); Range: (-∞, ∞)</h3>
Answer:
1/2, 2/3, 3/4, etc
i think thats what you need
Step-by-step explanation:
