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tamaranim1 [39]
3 years ago
7

Which would be a common-sense practice in a lab environment?

Physics
1 answer:
Elis [28]3 years ago
6 0
To wear PPE equipment and read all the instructions before preforming the lab
You might be interested in
¿Qué resistencia debe ser conectada en paralelo con una de 20 Ω para hacer una
ValentinkaMS [17]

Answer:

60 Ω

Explanation:

R(com) = 15 Ω

1/R(com) = 1/R1 + 1/R2 + 1/R3 ..... + 1/Rn

1/15 = 1/20 + 1/R2

1/R2 = 1/15 - 1/20

1/R2 = (4 - 3) / 60

1/R2 = 1/60

R2 = 60 Ω

así, la combinada de resistencia necesaria es 60 Ω

5 0
3 years ago
A physicist drives through a stop light. When he is pulled over, he tells the police officer that the Doppler shift made the red
Alik [6]

Answer:

Speed of physicist car is 0.036c or 1.08 x 10⁷ m/s .

Explanation:

Doppler Effect is defined as the change in frequency or wavelength of the wave as the source or/and observer moving away or towards each other.

In this case, the Doppler effect equation in terms of wavelength is :

\lambda_{s} = \lambda_{o}\sqrt{\frac{1-\frac{v}{c} }{1+\frac{v}{c} } }       ......(1)

Here \lambda_{s} is source wavelength, \lambda_{o} is observed wavelength, v is speed of the observer and c is the speed of light.

Given :

Source wavelength, \lambda_{s} = 660 nm = 660 x 10⁻⁹ m

Observed wavelength, \lambda_{0} = 555 nm = 555 x 10⁻⁹ m

Substitute these values in the equation (1).

555\times10^{-9} } = 660\times10^{-9} \sqrt{\frac{1-\frac{v}{c} }{1+\frac{v}{c} } }

\sqrt{\frac{1-\frac{v}{c} }{1+\frac{v}{c} } } = 0.84

{\frac{1-\frac{v}{c} }{1+\frac{v}{c} } } = (0.84)^{2} = 0.7056

1-\frac{v}{c}=0.7056+0.7056\frac{v}{c}

\frac{v}{c}=\frac{0.2944}{8.056}

v = 0.036c=0.036\times3\times10^{8}

v = 1.08 x 10⁷ m/s  

8 0
3 years ago
Complete the sentence below using one of the following
astra-53 [7]

Answer:

equilibrium

Explanation:

acceleration will remain constant

3 0
3 years ago
If a wave's third harmonic has a frequency of 24 Hz, what is its
Charra [1.4K]

Answer:

8 Hz, 48 Hz

Explanation:

The standing waves on a string (or inside a pipe, for instance) have different modes of vibrations, depending on how many segments of the string are vibrating.

The fundamental frequency of a standing wave is the frequency of the fundamental mode of vibration; then, the higher modes of vibration are called harmonics. The frequency of the n-th harmonic is given by

f_n = nf_1

where

f_1 is the fundamental frequency

In this problem, we know that the wave's third harmonic has a frequency of

f_3=24 Hz

This means this is the frequency for n = 3. Therefore, we can find the fundamental frequency as:

f_1=\frac{f_3}{3}=\frac{24}{3}=8 Hz

Now we can also find the frequency of the 6-th harmonic using n = 6:

f_6 = 6 f_1 = 6 (8)=48 Hz

6 0
3 years ago
A star is estimated to be 4.8 km away from the earth. When we see this star in the night sky how old is the image. Let the speed
andre [41]

Time = distance / speed

Time = (4,800 meters) / (3 x 10⁸ m/s)

<em>Time = 0.000016 second</em>

This number is not one of the choices on the list.  My hunch is that you copied the distance wrong.

If the estimated distance to the star is actually 4.8 x 10¹⁵ km, instead of 4.8 km, then the answer would be close to 500 years <em>(B)</em>.

There's no way a star can be "4.8 km away from the Earth".  You can <em>walk</em> that far in about an hour, and passenger jet airplanes fly <em>twice</em> as far as that away from the Earth !

5 0
3 years ago
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