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3 years ago

Which would be a common-sense practice in a lab environment?

Physics

1 answer:

Elis [28]3 years ago

6 0

To wear PPE equipment and read all the instructions before preforming the lab

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Use Stefan's law to find the intensity of the cosmic background radiation emitted by the fireball of the Big Bang at a temperatu

Rus_ich [418]

Complete Question

Use Stefan's law to find the intensity of the cosmic background radiation emitted by the fireball of the Big Bang at a temperature of 2.81 K. Remember that Stefan's Law gives the Power (Watts) and Intensity is Power per unit Area (W/m2).

Answer:

The intensity is $I = 3.535 *10^{-6} \ W/m^2$

Explanation:

From the question we are told that

The temperature is $T = 2.81 \ K$

Now According to Stefan's law

$Power(P) = \sigma * A * T^4$

Where $\sigma$ is the Stefan Boltzmann constant with value $\sigma = 5.67*10^{-8} m^2 \cdot kg \cdot s^{-2} K^{-1}$

Now the intensity of the cosmic background radiation emitted according to the unit from the question is mathematically evaluated as

$I = \frac{P}{A}$

=> $I = \frac{\sigma * A * T^4}{A}$

=> $I = \sigma * T^4$

substituting values

$I = 5.67 *10^{-8} * (2.81)^4$

$I = 3.535 *10^{-6} \ W/m^2$

4 0

3 years ago

White light passes through a yellow stained glass window onto the floor. What color flashlight can you shine to create a white s

wolverine [178]

Yesssssssssssssssssss I can

8 0

4 years ago

The New England Merchants Bank Building in Boston is 152 m high. On windy days it sways with a frequency of 0.17 Hz, and the acc

aksik [14]

Answer:

d = 8.4 cm

Explanation:

In order to calculate the amplitude of oscillation of the top of the building, you use the following formula for the max acceleration of as simple harmonic motion:

$a_{max}=A\omega^2$ (1)

A: amplitude of the oscillation

w: angular speed of the oscillation = 2 $\pi$ f

f: frequency = 0.17Hz

The maximum acceleration of the top of the building is a 2.0% of the free-fall acceleration. Then, you have:

$a_{max}=0.02(9.8m/s^2)=0.196\frac{m}{s^2}$

Then, you solve for A in the equation (1) and replace the values of the parameters:

$A=\frac{a_{max}}{\omega^2}=\frac{a_{max}}{4\p^2i f^2}\\\\A=\frac{0.196m/s^2}{16\pi^2(0.17Hz)^2}\\\\A=0.042m=4.2cm$

The total distance, side to side, of the oscilation of the top of the building is twice the amplitude A. Then you obtain:

d = 2A = 2(4.2cm) = 8.4cm

4 0

4 years ago

A stone is dropped from a high cliff vertically. After 6

bonufazy [111]

Answer:

Ay=v₂t + ½ gt² is the best choice to solve this problem.

The height of the cliff is = 176.4 meters.

Explanation:

Given,

initial velocity = 0m/s as it is dropped vertically

acceleration = g = 9.8 m/s²

time = 6s

Height =?

Using the equation Ay=v₂t + ½ gt², we can calculate Ay, which is the height.

So,

Ay=v₂t + ½ gt²

by substituting v, t, and g, we get:

Ay= 0 × 6 + ½ × 9.8 × 6²

Ay = 0 + 4.9 × 36

Ay = 176.4 m

4 0

1 year ago

Layne conducted an investigation using objects and light. She determined that light behaves differently depending on the medium.

Crazy boy [7]

i think the answer is a hope this helped

6 0

3 years ago