Answer:
It's centripetal acceleration is 301.7 m/s²
Explanation:
The formula to be used here is that of the centripetal acceleration which is
ac = rω²
where ac is the centripetal acceleration = ?
ω is the angular velocity = 3 revolutions per second is to be converted to radian per second: 3 × 2π = 3 × 2 × 3.14 = 18.84 rad/s
r is the radius = 0.85 m
ac = 0.85 × 18.84²
ac = 301.7 m/s²
It's centripetal acceleration is 301.7 m/s²
Answer:
The diameter is 0.000056 m
Explanation:
Lets explain the relation between the meter and the micrometer
1 Meter is equal to 1000000 (one million) micrometers
1 micrometer = 
The symbol of the meter is m
The symbol of micrometer is μm
A human hair is approximately 56 µm in diameter
We need to express this diameter in meter
To do that we divide this number by 1,000,000 or multiply it by 
→ 
56 µm = 0.000056 m
→ OR
→ 
→ 56 µm = 0.000056 m
<em>The diameter is 0.000056 m</em>
Answer:
The Eurasian Plate
Explanation:
The Eurasian plate is one of the most extended on Earth, crossing all of Asia and Europe. The Eurasian plate is between the North American and the African Plates on the north and west sides. The Eurasian plate crushed up above the Indian plate. The Tibetan plateau and the Himalayan mountain range formed due to the crush between the Eurasian Plate and Indian Plate, which started 50 million years ago.
<span>Each of these systems has exactly one degree of freedom and hence only one natural frequency obtained by solving the differential equation describing the respective motions. For the case of the simple pendulum of length L the governing differential equation is d^2x/dt^2 = - gx/L with the natural frequency f = 1/(2π) √(g/L). For the mass-spring system the governing differential equation is m d^2x/dt^2 = - kx (k is the spring constant) with the natural frequency ω = √(k/m). Note that the normal modes are also called resonant modes; the Wikipedia article below solves the problem for a system of two masses and two springs to obtain two normal modes of oscillation.</span>
Answer:
The Magnifying power of a telescope is 
Explanation:
Radius of curvature R = 5.9 m = 590 cm
focal length of objective 
= 
⇒ = 
⇒ = 295 cm
Focal length of eyepiece 
= 2.7 cm
Magnifying power of a telescope is given by,
therefore the Magnifying power of a telescope is
