Answer:
Increase
As the mass of either object increases, the force of gravitational attraction between them also increases.
Explanation:
The gravitational force is directly proportional to the mass of both interacting objects, more massive objects will attract each other with a greater gravitational force.
As the mass of either object increases, the force of gravitational attraction between them also increases.
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Use the velocity expression for uniform acceleration and solve for t: v = v0 + at. v0 is zero since the object is at rest. 49 m/s = a(t), and solve for t. t = 49 m/s / 9.8 = 5 seconds.
Answer:
15 deg
Explanation:
Assume both snowballs are thrown with the same initial speed 27.2 m/s. The first snowball is thrown at an angle of 75◦ above the horizontal. At what angle should you throw the second snowball to make it hit the same point as the first? The acceleration of gravity is 9.8 m/s 2 . Answer in units of ◦ .
Given:
For first ball, θ1 = 75◦
initial velocity for both the balls, u = 27.2 m/s
for second ball, θ2 = ?
since distance covered by both the balls is same.
Therefore,..
R1=(u^{2} sin2\alpha _{1}) /g[/tex]
the range for the first ball
the range for the second ball
R2=(u^{2} sin2\alpha _{2}) /g[/tex]
(u^{2} sin2\alpha _{2}) /g[/tex]=(u^{2} sin2\alpha _{1}) /g[/tex]
sin2\alpha _{2})=sin2\alpha _{1})
=sin^-1(sin2\alpha _{1})
=1/2sin^-1(sin2\alpha _{1})
=
15 deg
Answer: e. P/2
Explanation:
For ideal gases, we have the relation:
P*V = n*R*T
where:
n = number of mols
R = Gas constant
T = temperature
V = volume
P = pressure.
We know that for sample A, we have n moles, a temperature T and a volume V, then the pressure of this sample will be:
Pa = (n*R*T)/V.
For sample B, we have:
n/2 moles, temperature T/2 and a volume V/2, then the pressure will be:
Pb = (n/2)*R*(T/2)*(2/V) = (n*R*T/V)*(2/4)
and:
(n*R*T/V) = Pa
Then we can replace it and we get:
Pb = (n*R*T/V)*(2/4) = Pa*(2/4) = Pa*(1/2) = Pa/2.
Then the correct option is e.
You can use photo math for This
