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bekas [8.4K]
3 years ago
10

A 5 Kg bowling ball is thrown at a stationary 1.6 Kg bowling pin at 5 m/s. If the final velocity of the ball is 2.5 m/s. The fin

al velicoty of the bowling pin is _____m/s. ​
Physics
1 answer:
Sergio039 [100]3 years ago
7 0

Answer: hope this helps

Explanation:

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State newtons second law of motion from the equation f: ma​
ANEK [815]

Answer:

wut goes up must come down i dunno lol

Explanation:

5 0
3 years ago
a pendulum, 2.0 m in length, is released with a push when the string is at an angle of 25 o from the vertical. if the initial sp
stiks02 [169]

Answer:

1 / 2 m v^2 = L m g (1 - cos θ)

This is the KE due to the pendulum falling from a 25 deg displacement

v^2 = 2 L g (1 - cos 25) = 2 * 2 * 9.8 (1 - .906) = 3.67 m^2/s^2

v = 1.92 m/s      this is the speed due to an initial displacement of 25 deg

Its speed at the bottom would then be

1.92 + 1.2 = 3.12 m/s   since it gains 1.92 m/s from its initial displacement

3 0
1 year ago
The component of the ball's velocity whose magnitude is most affected by the collisions is
bazaltina [42]
<span>The component most affected by the collisions is vertical. The ball's vertical will either decrease or increase due to the collision. If the velocity is high during the collsion the ball's vertical will likely be higher and if the ball's velocity is low the vertical will be as well.</span>
8 0
3 years ago
An ice skater starts with a velocity of 2.25 m/s in a 50.0 direction. after 8.33 m/s in a 120 direction. what is the y-component
Bond [772]

The y-component of the acceleration is 0.33 m/s^2

Explanation:

The y-component of the acceleration is given by:

a_y = \frac{v_y-u_y}{t}

where

v_y is the y-component of the  final velocity

u_y is the y-component of the initial velocity

t is the time elapsed

For the ice skater in this problem, we have:

u_y = u sin \theta_1 = (2.25 m/s)(sin 50.0^{\circ})=1.72 m/s

where

u = 2.25 m/s is the initial velocity

\theta_1 = 50.0^{\circ} is the initial  direction

v_y = v sin \theta_2 = (4.65)(sin 120^{\circ})=4.03 m/s, where

v = 4.65 m/s is the final velocity

\theta_2 = 120.0^{\circ} is the final direction

The time elapsed is

t = 8.33 s

Therefore, we can find the y-component of the acceleration:

a_y=\frac{4.03-1.72}{8.33}=0.33 m/s^2

Learn more about acceleration:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

3 0
3 years ago
What is frictional less pulley​
Talja [164]

Answer:

Conditions under which the belt and pulleys are operating – The friction between the belt and pulley may decrease substantially if the belt happens to be muddy or wet, as it may act as a lubricant between the surfaces.

Explanation:

I hope that this would be helpful

7 0
3 years ago
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