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3 years ago

A student increases the temperature of a 300 cm^3 balloon from 30c to 60c. what will the new volume of the ballon be

2 answers:

5 0

This problem uses the ideal gas law, PV = nRT. T for temperature must be in Kelvin, so we add 273.15 to the Celsius temperatures. We are then changing T from 303.15 K to 333.15K. The ratio of the temperatures 333.15/303.15 ~= 1.1. So holding pressure constant, the new volume of the balloon will be approximately 10% larger, or 330cm^3.

Mama L [17]3 years ago

4 0

From Charles law the volume of a fixed mass of gas is directly proportional to the absolute temperature when pressure is kept constant.
Volume α temperature, mathematically; k = V/T
Therefore, comparing two gases V1/T1 = V2/T2
V1 =300 cm³ T1= 30°C (30 +273= 303K) V2= ? T2= 60°C (60 +273= 333K)
Thus, 300/303 = V2/333
V2 = (300 × 333)/ 303
= 329.703 cm³
Hence the new volume will be 329.703 cm³

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Sound waves can NOT travel through the vacuum of space?

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3 years ago

2. If a rock fell down a cliff and hit the bottom of the ravine at 4 seconds, how fast was the rock

Iteru [2.4K]

Answer: -39.2 m/s or 39.2 m/s directed downwards

Explanation:

This situation is a good example of Free Fall, where the main condition is that the initial velocity must be zero $V_{o}=0$ , and the acceleration is constant (acceleration due gravity).

So, in order to calculate the final velocity $V$ of the rock just at the moment it hitsthe bottom of the cliff, we will use the following equation:

$V={V_{o}}^{2}+gt$

Where:

$g=-9.8 m/s^{2}$ is the acceleration due gravity (directed downwards)

$t=4 s$ is the time it takes to the rock to fall down the cliff

$V=(-9.8 m/s^{2})(4 s)$

$V=-39.2 m/s$ This is the rock's final velocity and its negative sign indicates it is directed downwards

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3 years ago

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A pencil rolls horizontally of a 1 meter high desk and lands .25 meters from the base of the desk. How fast was the pencil rolli

vovikov84 [41]

Answer: 0.55 m/s

Explanation:

This situation is related to projectile motion (also called parabolic motion), where the main equations are as follows:

$x=V_{o} cos\theta t$ (1)

$y=y_{o}+Vo sin \theta t + \frac{g}{2}t^{2}$ (2)

Where:

$x=0.25 m$ is the horizontal displacement of the pencil

$V_{o}$ is the pencil's initial velocity

$\theta=0\°$ since we are told the pencil rolls horizontally before falling

$t$ is the time since the pencil falls until it hits the ground

$y_{o}=1 m$ is the initial height of the pencil

$y=0$ is the final height of the pencil (when it finally hits the ground)

$g=-9.8m/s^{2}$ is the acceleration due gravity, always acting vertically downwards

Begining with (1):

$x=V_{o} cos(0\°) t$ (3)

$x=V_{o}t$ (4)

Finding $t$ from (2):

$0=1 m+ \frac{-9.8m/s^{2}}{2}t^{2}$ (5)

$t=\sqrt{\frac{-2y_{o}}{g}}$ (6)

Substituting (6) in (4):

$x=V_{o}\sqrt{\frac{-2y_{o}}{g}}$ (7)

Isolating $V_{o}$ :

$V_{o}=\frac{x}{\sqrt{\frac{-2y_{o}}{g}}}$ (8)

$V_{o}=\frac{0.25 m}{\sqrt{\frac{-2(1 m)}{-9.8m/s^{2}}}}$ (9)

Finally:

$V_{o}=0.55 m/s$

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2 years ago

Discuss the chemical bond exist in silicon crystal?

tamaranim1 [39]

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2 years ago

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