Potassium hydroxide (KOH) and
hydrochloric acid (HCl) react in a beaker. They form potassium chloride (KCl)
and water (H2O). This type of reaction is a double replacement reaction wherein
the two principal reactants exchange after the reaction. The Cl will combine to
the K forming KCl and the H will add to the OH forming H2O.
Conservation of momentum: total momentum before = total momentum after
Momentum = mass x velocity
So before the collision:
4kg x 8m/s = 32
1kg x 0m/s = 0
32+0=32
Therefore after the collision
4kg x 4.8m/s = 19.2
1kg x βm/s = β
19.2 + β = 32
Therefore β = 12.8 m/s
Answer is B hope this helps
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Answer:
<u>
, where v2= velocity at the end and v1= velocity in the beggining</u>
Explanation:
<u>Asuming that v=K, where k= velocity lower than 60[km/h] we can make an equation for a average speed to entire trip as follows:</u>
<u>The equation of average is: , where v2= velocity at the end and v1= velocity in the beggining. Where v1=60 [km/h] becouse is the average velocity of half trip, and v2=k.</u>
<u>That means that jhon´s average speed decreses</u>
