Now the aim of the above discussion is to internalize the mathematical relationships for open-end air columns in order to perform calculations predicting the length of air column required to produce a given natural frequency. And conversely, calculations can be performed to predict the natural frequencies produced by a known length of air column. Each of these calculations requires knowledge of the speed of a wave in air (which is approximately 340 m/s at room temperatures). The graphic below depicts the relationships between the key variables in such calculations. These relationships will be used to assist in the solution to problems involving standing waves in musical instruments.
Step-by-step explanation:
Given that,
Perpendicular = 17 units
Hypotenuse = 25 units
We need to find the value of x.
Using Pythagoras theorem to find x.
Hypotenuse² = base²+perpendicular²
25² = x² + 17²
x = 18.3 units
So, the value of x is equal to 18.3 units. No, the sides do not form a Pythagorean triplet.
4/7 because the equation would be 2(7-5)
over
5+2
so it would be
2(2)
over
7
and then it would be
4
over
7
Let C be Clowns R Fun charge for b balloons and S be Singing Balloons charge.
C=6+1.25b and S=2+1.95b. C must be less than S.
6+1.25b<2+1.95b, 4<0.7b, b>4/0.7, b>40/7, b>5. So Mrs Travis needs to purchase more than 5 balloons.
That would be D. The first two would be fight (I think) except they don't include turning the calculator on. C is just plain wrong. D has all the right keystrokes.
