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pickupchik [31]
2 years ago
6

[A] Write an expression for the equivalent resistance of three resistors connected in parallel.[ no derivation needed]

Physics
1 answer:
anzhelika [568]2 years ago
4 0

Answer:

1) R1 + ((R2 × R3)/(R2 + R3))

2) 0.5 A

3) 3.6 V

Explanation:

1) We can see that resistors R2 and R3 are in parallel.

Formula for sum of parallel resistors; 1/Rt = 1/R2 + 1/R3

Making Rt the subject gives;

Rt = (R2 × R3)/(R2 + R3)

Now, Resistor R1 is in series with this sum of R2 and R3. Thus;

Total resistance of circuit = R1 + ((R2 × R3)/(R2 + R3))

2) R_total = R1 + ((R2 × R3)/(R2 + R3))

We are given;

R1 = 7.2 Ω

R2 = 8 Ω

R3 = 12 Ω

R_total = 7.2 + ((8 × 12)/(8 + 12))

R_total = 7.2 + 4.8

R_total = 12 Ω

Formula for current is;

I = V/R

I = 6/12

I = 0.5 A

3) since current through the circuit is 0.5 and R1 is 7.2 Ω.

Thus, potential difference through R1 is;

V = IR = 0.5 × 7.2 = 3.6 V

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Monica [59]

Answer:

6 Minutes 40 Seconds or 400 Seconds

Explanation:

Time to cover a distance of 5m = 1 Second

Time to cover a distance of 2000m = 2000÷5

= 400 Seconds

After converting 400 Seconds into minutes it will become 6 minutes 40 seconds.

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2 years ago
A van has a weight of 4000 lb and center of gravity at Gv. It carries a fixed 900 lb load which has a center of gravity at Gl. I
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Answer:

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Explanation:

To solve this exercise we can use Newton's second law.

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       N_B + N_A = W_van + W_load

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        m = (W_van + W_load) / g

the friction force has the expression

      fr = μ N_{total}

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we substitute

      a = μ (W_van + W_load)    \frac{g}{W_van + W_load}

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taking the acceleration let's use the kinematic relations where the final velocity is zero

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5 0
3 years ago
A weightlifter lifts a weight of 500 N from the ground over her head, a distance of 1.8 m. How much work has been done to move t
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Answer is 900N

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3 0
2 years ago
What is the resistance of a resistor if the potential difference across the resistor is 1.6 V when a current of 0.5 A flows thro
MrRa [10]

Answer:

3.2Ω

Explanation:

V= IR

1.6V = 0.5A × R

R= 1.6/0.5

  1. R= 3.2Ω
3 0
3 years ago
An independent-measures design is also known as a _______________ design.
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An Independent Group/ between-subjects design differs from a within-subjects design in that a between-subjects design. The correct option is B.

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Each participant in a topic or intergroup design only encounters one condition, and the group differences between individuals under various conditions are compared. The in-subject design, in which every participant is exposed to every condition, is the antithesis of this.

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