Answer:
J for impulse
t for time
F for force
formula is J=F×t
Explanation:
putting values in eqs after rearranging
we need to find force so
F=J ÷t
F=400÷15
=26.67
=27(rounded off)
27N is the Force applied.
The distance from a 27 mw point source of electromagnetic waves where the electric field amplitude 0. 060 v/m will be 21.21 m .
Electromagnetic waves or EM waves are waves that are created as a result of vibrations between an electric field and a magnetic field. In other words, EM waves are composed of oscillating magnetic and electric fields.
The highest point of a wave is known as 'crest' , whereas the lowest point is known as 'trough'. Electromagnetic waves can be split into a range of frequencies. This is known as the electromagnetic spectrum.
c = 3 *
m/s
∈ = 8.85 *
/ N/ 
E = 0. 060 v/m
I = P / 4π
Also , I = c ∈
/2
= P / 4π I equation 1
substituting the value of I in equation 1
= 2 P / 4π (c ∈
)
= 2 * 27 *
/ 4 * 3.14 * 3 *
* 8.85 *
* 
r = 21.21 m
To learn more about Electromagnetic waves here
brainly.com/question/12392559
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Answer:
The value is the temperature of the air inside the tire
340.54 K
% of the original mass of air in the tire should be released 99.706 %
Explanation:
Initial gauge pressure = 2.7 atm
Absolute pressure at inlet
= 2.7 + 1 = 3.7 atm
Absolute pressure at outlet
= 3.2 + 1 = 4.2 atm
Temperature at inlet
= 300 K
(a) Volume of the system is constant so pressure is directly proportional to the temperature.


340.54 K
This is the value is the temperature of the air inside the tire
(b). Since volume of the tyre is constant & pressure reaches the original value.
From ideal gas equation P V = m R T
Since P , V & R is constant. So
m T = constant




value of the original mass of air in the tire should be released is

⇒ -0.99706
% of the original mass of air in the tire should be released 99.706 %.
There is no pic
Can you plz take to question better <span />