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galina1969 [7]
3 years ago
6

Please help on magnitude !

Physics
1 answer:
emmainna [20.7K]3 years ago
4 0

Answer:

Yes, the answer is 100 N

Explanation:

Car is pushed right with 150 N and obviously frictional force will act in the opposite direction of the fore provided and that is 50 N

Hence, 150 - 50 is 100 N

Magnitude is 100 N

Direction is Towards the right

Since they asked for Magnitude the answer should be 100 N

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If an impulse of 400 Ns acts on an object for 15s, what is the force of the object?
Ksju [112]

Answer:

J for impulse

t for time

F for force

formula is J=F×t

Explanation:

putting values in eqs after rearranging

we need to find force so

F=J ÷t

F=400÷15

=26.67

=27(rounded off)

27N is the Force applied.

7 0
3 years ago
At what distance from a 27 mw point source of electromagnetic waves is the electric field amplitude 0. 060 v/m ?
n200080 [17]

The distance from a 27 mw point source of electromagnetic waves where the electric field amplitude 0. 060 v/m will be 21.21 m .

Electromagnetic waves or EM waves are waves that are created as a result of vibrations between an electric field and a magnetic field. In other words, EM waves are composed of oscillating magnetic and electric fields.

The highest point of a wave is known as 'crest' , whereas the lowest point is known as 'trough'. Electromagnetic waves can be split into a range of frequencies. This is known as the electromagnetic spectrum.

c = 3 * 10^{8} m/s

∈ = 8.85 * 10^{- 12} C^{2} / N/ m^{2}

E = 0. 060 v/m

I = P / 4πr^{2}

Also , I = c ∈ E^{2} /2

r^{2} = P / 4π I                                 equation 1

substituting the value of I in equation 1

r^{2} = 2 P / 4π (c ∈ E^{2} )

r^{2} = 2 * 27 * 10^{-3} / 4 * 3.14 * 3 * 10^{8} * 8.85 * 10^{- 12}  * (0.06)^{2}

r = 21.21 m

To learn more about Electromagnetic waves  here

brainly.com/question/12392559

#SPJ4

5 0
2 years ago
Before beginning a long trip on a hot day, a driver inflates anautomobile tire to a gauge pressure of 2.70 atm at 300 K. At the
anygoal [31]

Answer:

The value is the temperature of the air inside the tire T_{2} = 340.54 K

% of the original mass of air in the tire should be released 99.706 %

Explanation:

Initial gauge pressure = 2.7 atm

Absolute pressure at inlet P_{1} = 2.7 + 1 = 3.7 atm

Absolute pressure at outlet P_{2} = 3.2 + 1 = 4.2 atm

Temperature at inlet T_{1} = 300 K

(a) Volume of the system is constant so  pressure is directly proportional to the temperature.

\frac{T_{2} }{T_{1} } = \frac{P_{2} }{P_{1} }

\frac{T_{2} }{300}  = \frac{4.2}{3.7}

T_{2} = 340.54 K

This is the value is the temperature of the air inside the tire

(b). Since volume of the tyre is constant & pressure reaches the original value.

From ideal gas equation P V = m R T

Since P , V & R is constant. So

m T = constant

m_{1}  T_{1} =  m_{2}  T_{2}

\frac{m_{2} }{m_{1}  } = \frac{T_{1} }{T_{2} }

\frac{m_{2} }{m_{1}  } = \frac{300}{354.54}

\frac{m_{2} }{m_{1}  } =0.00294

value of  the original mass of air in the tire should be released is  \frac{m_{2} - m_{1}}{m_{1}}

\frac{0.00294-1}{1}

⇒ -0.99706

% of the original mass of air in the tire should be released 99.706 %.

8 0
3 years ago
If you view a complete free body diagram of a moving object, what two aspects of the body's motion will the diagram show?
kirill115 [55]
There is no pic 
Can you plz take to question better  <span />
5 0
3 years ago
Please help me with this! (:
tiny-mole [99]

Answer:

(A) 18 km/h

Explanation:

4.9\frac{m}{s}=4.9\cdot \frac{\frac{1}{1000}km}{\frac{1}{3600}h}=4.9\cdot3.6\frac{km}{h}=17.64\frac{km}{h}\approx18\frac{km}{h}

8 0
3 years ago
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