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galina1969 [7]
3 years ago
6

Please help on magnitude !

Physics
1 answer:
emmainna [20.7K]3 years ago
4 0

Answer:

Yes, the answer is 100 N

Explanation:

Car is pushed right with 150 N and obviously frictional force will act in the opposite direction of the fore provided and that is 50 N

Hence, 150 - 50 is 100 N

Magnitude is 100 N

Direction is Towards the right

Since they asked for Magnitude the answer should be 100 N

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Lostsunrise [7]

Answer:

what is this question

Explanation:

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8 0
3 years ago
53. A recently discovered planet has a mass four times as great as Earth's and a radius twice as large as Earth's. What will be
marusya05 [52]

Answer:

g' = g = 9.81 m/s^2

so gravity will be same as that of surface of earth

Explanation:

As we know that the acceleration due to gravity is given as

g = \frac{GM}{R^2}

here we have

M = 4M_e

R = 2R_e

we know that for earth we have

g = 9.81 = \frac{GM_e}{R_e^2}

now if the radius and mass is given as above

g' = \frac{G(4M_e)}{(2R_e)^2}

g' = \frac{GM_e}{R_e^2}

g' = g = 9.81 m/s^2

so gravity will be same as that of surface of earth

6 0
3 years ago
What is Otter's average velocity over his entire trip when it takes him 2 minutes to walk 100 meters north and another 1 minute
Leya [2.2K]

Answer:

0.50m/s

Explanation:

Average velocity is the change in displacement of a body with respect to time.

Velocity = ∆S/∆t

∆S = 100m - 70m

∆S = 30m

∆t = 2min - 1 min

∆t = 1min = 60secs

Substitute the given parameters into the formula for velocity

Velocity = 30m/60s

Velocity = 1/2 m/s

Average Velocity = 0.5m/s

7 0
3 years ago
A 2,100 kg car is lifted by a pulley. If the cable breaks at 4.50 m, what is the velocity of the car when it hits the ground? 88
sammy [17]
V^2-u^2=2as

v=final velocity=unkown
u=initial velocity=0 m/s, because freely falling
a=acceleration due to gravity=9.8 m/s^2
s=distance (here height) traveled=4.5m

therefore the final velocity,
v^2=2*9.8*4.5
v=<span>9.39m/s</span>
8 0
3 years ago
A hot-air balloon of diameter 12 mm rises vertically at a constant speed of 15 m/sm/s. A passenger accidentally drops his camera
jeka94

To solve this problem we will apply the linear motion kinematic equations. With the information provided we will calculate the time it takes for the object to fall. From that time, considering that the ascent rate is constant, we will take the reference distance and calculate the distance traveled while the object hit the ground, that is,

h = v_0 t -\frac{1}{2} gt^2

-18 = 15*t + \frac{1}{2} 9.8*t^2

t = 3.98s

Then the total distance traveled would be

h = h_0 +v_0t

h = 18+15*3.98

h = 77.7m

Therefore the railing will be at a height of 77.7m when it has touched the ground

5 0
3 years ago
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