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Mars2501 [29]
2 years ago
9

Free.... f..... r.... e.... e... FREE POINTS! (and brainliest ofc) Alright two more after this guys

Chemistry
2 answers:
Illusion [34]2 years ago
8 0

Answer:

o.k

Explanation:

alexgriva [62]2 years ago
5 0

Answer:

rawr

Explanation:

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How are science and technology related
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Science is the study of the world and how it works through collecting data using the scientific method. Technology is the application of that scientific knowledge to create devices that solve problems and carry out tasks.

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3 years ago
What is the total ionic equation for the following reaction?
schepotkina [342]

Answer: Option (d) is the correct answer.

Explanation:

An equation in which electrolytes are represented in the form of ions is known as an ionic equation.

Strong electrolytes easily dissociate into their corresponding ions. Hence, they form ionic equation.

H_{2}CrO_{4} is a strong acid and Ba(OH)_{2} is a strong bases, therefore, both of them will dissociate into ions.

Thus, total ionic equation will be as follows.

2H^{+} + CrO_{4}^{-} + Ba^{2+} + 2OH^{-} \rightarrow Ba^{2+} + CrO_{4}^{-} + 2H_{2}O

5 0
3 years ago
Read 2 more answers
an atom of chlorine has an amount number of 17 and a mass number of 37. how many protons neutrons, and electrons are in the atom
Soloha48 [4]

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6 0
2 years ago
Determine the value of the equilibrium constant, KgoalKgoalK_goal, for the reaction CO2(g)⇌C(s)+O2(g)CO2(g)⇌C(s)+O2(g), Kgoal=?
NISA [10]

Answer:

The value of the equilibrium constant for reaction asked is 1.24\times 10^{-7}.

Explanation:

CO_2(g)\rightleftharpoons C(s)+O_2(g)

K_{goal}=?

K_{goal}=\frac{[C][O_2]}{[CO_2]}

2CO_2(g)+2H_2O(l)\rightleftharpoons CH_3COOH(l)+2O_2(g)..[1]

K_1=\frac{[CH_3COOH][O_2]^2}{[CO_2]^2[H_2O]^2}

2H_2(g)+O2(g)\rightleftharpoons 2H_2O(l)..[2]

K_2=\frac{[H_2O]^2}{[H_2]^2[O_2]}

CH_3COOH(l)\rightleftharpoons 2C(s)+2H_2(g)+O_2(g)..[3]

K_3=\frac{[C]^2[H_2]^2[O_2]}{[CH_3COOH]}

[1] +  [2] + [3]

2CO_2(g)\rightleftharpoons 2C(s)+2O_2(g)

 ( on adding the equilibrium constant will get multiplied with each other)

K=K_1\times K_2\times K_3

K=5.40\times 10^{-16}\times 1.06\times 10^{10}\times 2.68\times 10^{-9}

K=1.53\times 10^{-14}

K=\frac{[C]^2[O_2]^2}{[CO_2]^2}

On comparing the K and K_{goal}:

K^2=K_{goal}

K_{goal}=\sqrt{K}=\sqrt{1.53\times 10^{-14}}=1.24\times 10^{-7}

The value of the equilibrium constant for reaction asked is 1.24\times 10^{-7}.

4 0
3 years ago
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