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Masteriza [31]
3 years ago
7

PLEASE HELP ME WIT DIS

Mathematics
2 answers:
ruslelena [56]3 years ago
8 0
The answer is v=208 in
Lunna [17]3 years ago
6 0

To make things easier, this solid can be divided in 3 parts:

- the first one is 2in long, 5in wide and 8in tall

- the second one is 2in long, 8in wide and 3in tall

- the third one is just like the first one, so 2in long, 5in wide and 8in tall

In order to find the volume of the solids, we need to multiply their dimensions:

1st: 2.5.8 = 80in^{3}

2nd: 2.8.3 = 48in^{3}\\

3rd: 2.5.8 = 80in^{3}

The volume of the big solid is equal to (80 + 48 + 80)in^{3}

V = 208in^{3}

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In a population of 10,000, there are 5000 nonsmokers, 2500 smokers of one pack or less per day, and 2500 smokers of more than on
Kazeer [188]

Answer:

In one month, we will have 4,950 non-smokers, 2,650 smokers of one pack and 2,400 smokers of more than one pack.

In two months, we will have 4,912 non-smokers, 2,756 smokers of one pack and 2,332 smokers of more than one pack.

In a year, we will have 4,793 non-smokers, 3,005 smokers of one pack and 2,202 smokers of more than one pack.

Step-by-step explanation:

We have to write the transition matrix M for the population.

We have three states (nonsmokers, smokers of one pack and smokers of more than one pack), so we will have a 3x3 transition matrix.

We can write the transition matrix, in which the rows are the actual state and the columns are the future state.

- There is an 8% probability that a nonsmoker will begin smoking a pack or less per day, and a 2% probability that a nonsmoker will begin smoking more than a pack per day. <em>Then, the probability of staying in the same state is 90%.</em>

-  For smokers who smoke a pack or less per day, there is a 10% probability of quitting and a 10% probability of increasing to more than a pack per day. <em>Then, the probability of staying in the same state is 80%.</em>

- For smokers who smoke more than a pack per day, there is an 8% probability of quitting and a 10% probability of dropping to a pack or less per day. <em>Then, the probability of staying in the same state is 82%.</em>

<em />

The transition matrix becomes:

\begin{vmatrix} &NS&P1&PM\\NS&  0.90&0.08&0.02 \\  P1&0.10&0.80 &0.10 \\  PM& 0.08 &0.10&0.82 \end{vmatrix}

The actual state matrix is

\left[\begin{array}{ccc}5,000&2,500&2,500\end{array}\right]

We can calculate the next month state by multupling the actual state matrix and the transition matrix:

\left[\begin{array}{ccc}5000&2500&2500\end{array}\right] * \left[\begin{array}{ccc}0.90&0.08&0.02\\0.10&0.80 &0.10\\0.08 &0.10&0.82\end{array}\right] =\left[\begin{array}{ccc}4950&2650&2400\end{array}\right]

In one month, we will have 4,950 non-smokers, 2,650 smokers of one pack and 2,400 smokers of more than one pack.

To calculate the the state for the second month, we us the state of the first of the month and multiply it one time by the transition matrix:

\left[\begin{array}{ccc}4950&2650&2400\end{array}\right] * \left[\begin{array}{ccc}0.90&0.08&0.02\\0.10&0.80 &0.10\\0.08 &0.10&0.82\end{array}\right] =\left[\begin{array}{ccc}4912&2756&2332\end{array}\right]

In two months, we will have 4,912 non-smokers, 2,756 smokers of one pack and 2,332 smokers of more than one pack.

If we repeat this multiplication 12 times from the actual state (or 10 times from the two-months state), we will get the state a year from now:

\left( \left[\begin{array}{ccc}5000&2500&2500\end{array}\right] * \left[\begin{array}{ccc}0.90&0.08&0.02\\0.10&0.80 &0.10\\0.08 &0.10&0.82\end{array}\right] \right)^{12} =\left[\begin{array}{ccc}4792.63&3005.44&2201.93\end{array}\right]

In a year, we will have 4,793 non-smokers, 3,005 smokers of one pack and 2,202 smokers of more than one pack.

3 0
3 years ago
Factor by grouping <br> 3x^2 + 11 - 14 <br><br><br><br> plss i need help!
8_murik_8 [283]

Answer:

3x^{2}+11-14 hi

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
Ayanna plans to bake 3 types of cookies to take to a party. She needs to be sure that she has enough flour. The chocolate cookie
djyliett [7]
The children brought 2+1+114=414 cups of flour and 14+12+34=112 cups of butter.

They have enough flour for

414÷34===174×43173523
batches and they have enough butter for

112÷13===32×3192412
batches, so the butter is the limiting factor. Thus, they can make 4 whole batches of a dozen cookies each.
7 0
2 years ago
Read 2 more answers
Find the area.<br> 2 cm<br> 6 cm<br> 4 cm
hammer [34]

Answer:

A=1/2(a+b)h

A=1/2(2cm+4cm)6cm

A=1/2×6cm×6cm

A=18cm²

3 0
2 years ago
The polynomial f(x) leaves a remainder of - 3 and - 7 when divided by (3x - 1) and (x +1) respectively.
olga55 [171]

Step-by-step explanation:

Here, f(x) is the given polynomial.

By remainder Theorem,

When divided by (3x-1),

f(1/3) = -3........(1)

When divided by (x+1),

f(-1) = -7.........(2)

<em>Another</em><em> </em><em>polynomial</em><em> </em><em>is</em><em> </em><em>3</em><em>x</em><em>²</em><em>+</em><em>2</em><em>x</em><em>-</em><em>1</em>

Solving,

3x²+2x-1

= 3x²+3x-x-1

=3x(x+1)-(x+1)

=(3x-1)(x+1)

So

f(x) = (3x-1)(x+1)Qx + (ax+b)

For f(-1),

-7 = -a+b

b= a-7

For f(1/3),

-3 = a/3+b

or, -3 = a/3+a-7

or, 4×3 = 4a

or a = 3

Also, b = 3-7 =-4

Hence, remainder is (3x-4)

7 0
3 years ago
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