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PolarNik [594]
3 years ago
5

A 1000-kg aircraft going 25 m/s collides with a 1500-kg aircraft that is parked. They stick

Physics
1 answer:
Sonbull [250]3 years ago
5 0

Answer:

48.54 m

Explanation:

Mass of moving aircraft = 1000 kg

Mass of stationary aircraft = 1500 kg

Velocity of moving aircraft = 25 m/s

Velocity by which they both move together = 10 m/s

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

v=u+at\\\Rightarrow 0=10+a\times 9.7\\\Rightarrow \frac{-10}{9.7}=a\\\Rightarrow a=-1.03\ m/s^2

v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{0^2-10^2}{2\times -1.03}\\\Rightarrow s=48.54\ m

Both planes skid a distance of 48.54 m

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We know that Fick's law is given by,

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Where \frac{\Delta c}{\Delta x} is the concentration of gradient

D is the diffusivity coefficient

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In the other hand we have, that

D= D_0 e^{\frac{E_d}{RT}}

Where D_0 is the proportionality constant,

R is the gas constant, T the temperature and E_d is the activation energy.

Replacing the value of diffusivity coefficient in Fick's law we have,

J = -D_0 ^{\frac{E_d}{RT}}\frac{\Delta c}{\Delta x}

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T=\frac{Ed}{Rln(\frac{J\Delta x}{D_0 \Delta c})}

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\Delta c = 0.664-0.339 = 0.325 C. cm^{-1}

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Substituting,

T=\frac{Ed}{Rln(\frac{J\Delta x}{D_0 \Delta c})}

T=-\frac{-82000}{(8.31)ln(\frac{3.2*10^{-9}(9.7*10^{-3})}{6.5*10^{-7} (0.325)})}

T=1118.07K=844\°C

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3 years ago
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