Drag Force = bv^2 = ma; a = g = 9.81 m/s^2
b = mg/v^2 = (0.0023×9.81)/(9.4^2)
b = 0.000255
Answer:
43.96 L
Explanation:
We are given that





We know that


Substitute the values


Hence, the volume of balloon at -14.8 degree Celsius=43.96 L
<span>which of those can we not get back once it has been used, the answer is oil or petroleum</span>
Answer:
NE she is abusing the color pink thats off limist and she is creepy