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Svetach [21]
3 years ago
12

When a pair of 10-N forces act on a box of candy, the net force on the box is

Physics
1 answer:
schepotkina [342]3 years ago
4 0

Answer:

D Any of the above depending on the directions of forces.

Explanation:

The net force on the box depends on the direction of the forces.

For example, we have three special cases:

- If the two forces are in the same direction, they add to each other, so the net force is

F = 10 N + 10 N = 20 N

- If the two forces are in opposite directions, the net force is given by the difference between the two forces, so

F = 10 N - 10 N = 0 N

- If the two forces are perpendicular to each other, their resultant is given by the Pythagorean theorem:

F=\sqrt{(10 N)^2 + (10 N)^2}=14.1 N

If the two forces are at any other angle, their resultant can be found by resolving each force along the x- and y- direction, and adding the components along each direction. The resultant net force will have a magnitude between 0 N and 20 N.

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Find the magnitude of the gravitational force a 63.5 kg person would experience while standing on the surface of Earth with a ma
Anastaziya [24]

Answer: 3976N

Explanation:

Using the formula for calculating gravitational force between two masses, we have

F = GMm/r^2

Where G is the gravitational constant

M and m are the masses

r is the distance between the masses

F= 6.673 × 10-¹¹ × 5.98 × 10²⁴ × 63.5/ (6.37 × 10^6)^2

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F= 0.3976×10⁴N

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3 0
3 years ago
The spring constant, k, for a 22cm spring is 50N/m. A force is used to stretch the spring and when it is measured again it is 32
lutik1710 [3]

Answer:

5N

Explanation:

Given parameters:

Original length = 22cm

Spring constant, K  = 50N/m

New length = 32cm

Unknown

Force applied  = ?

Solution:

The force applied on a spring can be derived using the expression below;

   Force  = KE

 k is the spring constant

 E is the extension

  extension = new length - original length

  extension  = 32cm  - 22cm  = 10cm

convert the extension from cm to m;  

   100cm  = 1m;

    10cm will give 0.1m

So;

  Force  = 50N/m x 0.1m  = 5N

8 0
3 years ago
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