2 x 2 <span>√ 3
You can multiple 2 by 2 because they both are outside numbers . But you can't multiple </span><span>√3 because it is inside the radical.
So.. the answer is 4</span><span>√3</span>
it would be 66 cause you know it
Answer:
<em>- 1.568</em>
Step-by-step explanation:
Let's assume that the base of the given logarithm is 10.
log m = 0.345 ⇒
= m
log n = 1.223 ⇒
= n
mn =
×
=
=
log
= - 1.568 × log 10 = <em>- 1.568</em>
Answer:
There is approximately 17% chance of a person not having a disease if he or she has tested positive.
Step-by-step explanation:
Denote the events as follows:
<em>D</em> = a person has contracted the disease.
+ = a person tests positive
- = a person tests negative
The information provided is:
![P(D^{c})=0.95\\P(+|D) = 0.98\\P(+|D^{c})=0.01](https://tex.z-dn.net/?f=P%28D%5E%7Bc%7D%29%3D0.95%5C%5CP%28%2B%7CD%29%20%3D%200.98%5C%5CP%28%2B%7CD%5E%7Bc%7D%29%3D0.01)
Compute the missing probabilities as follows:
![P(D) = 1- P(D^{c})=1-0.95=0.05\\\\P(-|D)=1-P(+|D)=1-0.98=0.02\\\\P(-|D^{c})=1-P(+|D^{c})=1-0.01=0.99](https://tex.z-dn.net/?f=P%28D%29%20%3D%201-%20P%28D%5E%7Bc%7D%29%3D1-0.95%3D0.05%5C%5C%5C%5CP%28-%7CD%29%3D1-P%28%2B%7CD%29%3D1-0.98%3D0.02%5C%5C%5C%5CP%28-%7CD%5E%7Bc%7D%29%3D1-P%28%2B%7CD%5E%7Bc%7D%29%3D1-0.01%3D0.99)
The Bayes' theorem states that the conditional probability of an event, say <em>A</em> provided that another event <em>B</em> has already occurred is:
![P(A|B)=\frac{P(B|A)P(A)}{P(B|A)P(A)+P(B|A^{c})P(A^{c})}](https://tex.z-dn.net/?f=P%28A%7CB%29%3D%5Cfrac%7BP%28B%7CA%29P%28A%29%7D%7BP%28B%7CA%29P%28A%29%2BP%28B%7CA%5E%7Bc%7D%29P%28A%5E%7Bc%7D%29%7D)
Compute the probability that a random selected person does not have the infection if he or she has tested positive as follows:
![P(D^{c}|+)=\frac{P(+|D^{c})P(D^{c})}{P(+|D^{c})P(D^{c})+P(+|D)P(D)}](https://tex.z-dn.net/?f=P%28D%5E%7Bc%7D%7C%2B%29%3D%5Cfrac%7BP%28%2B%7CD%5E%7Bc%7D%29P%28D%5E%7Bc%7D%29%7D%7BP%28%2B%7CD%5E%7Bc%7D%29P%28D%5E%7Bc%7D%29%2BP%28%2B%7CD%29P%28D%29%7D)
![=\frac{(0.01\times 0.95)}{(0.01\times 0.95)+(0.98\times 0.05)}\\\\=\frac{0.0095}{0.0095+0.0475}\\\\=0.1666667\\\\\approx 0.1667](https://tex.z-dn.net/?f=%3D%5Cfrac%7B%280.01%5Ctimes%200.95%29%7D%7B%280.01%5Ctimes%200.95%29%2B%280.98%5Ctimes%200.05%29%7D%5C%5C%5C%5C%3D%5Cfrac%7B0.0095%7D%7B0.0095%2B0.0475%7D%5C%5C%5C%5C%3D0.1666667%5C%5C%5C%5C%5Capprox%200.1667)
So, there is approximately 17% chance of a person not having a disease if he or she has tested positive.
As the false negative rate of the test is 1%, this probability is not unusual considering the huge number of test done.
Answer:
twice. (2)
Step-by-step explanation:
1 in 5 times you play, you'll win. every time you play 5 times, you'll win one, so if you play 10 times (double) you'll win double (twice)