Answer:
I is clear that, the linear equation
has no solution.
Step-by-step explanation:
<u>Checking the first option:</u>
![\frac{2}{3}\left(9x+6\right)=6x+4](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B3%7D%5Cleft%289x%2B6%5Cright%29%3D6x%2B4)
![6x+4=6x+4](https://tex.z-dn.net/?f=6x%2B4%3D6x%2B4)
![\mathrm{Subtract\:}4\mathrm{\:from\:both\:sides}](https://tex.z-dn.net/?f=%5Cmathrm%7BSubtract%5C%3A%7D4%5Cmathrm%7B%5C%3Afrom%5C%3Aboth%5C%3Asides%7D)
![6x+4-4=6x+4-4](https://tex.z-dn.net/?f=6x%2B4-4%3D6x%2B4-4)
![6x=6x](https://tex.z-dn.net/?f=6x%3D6x)
![\mathrm{Subtract\:}6x\mathrm{\:from\:both\:sides}](https://tex.z-dn.net/?f=%5Cmathrm%7BSubtract%5C%3A%7D6x%5Cmathrm%7B%5C%3Afrom%5C%3Aboth%5C%3Asides%7D)
![6x-6x=6x-6x](https://tex.z-dn.net/?f=6x-6x%3D6x-6x)
![0=0](https://tex.z-dn.net/?f=0%3D0)
![\mathrm{Both\:sides\:are\:equal}](https://tex.z-dn.net/?f=%5Cmathrm%7BBoth%5C%3Asides%5C%3Aare%5C%3Aequal%7D)
![\mathrm{True\:for\:all}\:x](https://tex.z-dn.net/?f=%5Cmathrm%7BTrue%5C%3Afor%5C%3Aall%7D%5C%3Ax)
<u>Checking the 2nd option:</u>
![5x+12=5x-7](https://tex.z-dn.net/?f=5x%2B12%3D5x-7)
![\mathrm{Subtract\:}5x\mathrm{\:from\:both\:sides}](https://tex.z-dn.net/?f=%5Cmathrm%7BSubtract%5C%3A%7D5x%5Cmathrm%7B%5C%3Afrom%5C%3Aboth%5C%3Asides%7D)
![5x+12-5x=5x-7-5x](https://tex.z-dn.net/?f=5x%2B12-5x%3D5x-7-5x)
![\mathrm{Simplify}](https://tex.z-dn.net/?f=%5Cmathrm%7BSimplify%7D)
![12=-7](https://tex.z-dn.net/?f=12%3D-7)
![\mathrm{The\:sides\:are\:not\:equal}](https://tex.z-dn.net/?f=%5Cmathrm%7BThe%5C%3Asides%5C%3Aare%5C%3Anot%5C%3Aequal%7D)
![\mathrm{No\:Solution}](https://tex.z-dn.net/?f=%5Cmathrm%7BNo%5C%3ASolution%7D)
<u>Checking the 3rd option:</u>
![4x+7=3x+7](https://tex.z-dn.net/?f=4x%2B7%3D3x%2B7)
![\mathrm{Subtract\:}7\mathrm{\:from\:both\:sides}](https://tex.z-dn.net/?f=%5Cmathrm%7BSubtract%5C%3A%7D7%5Cmathrm%7B%5C%3Afrom%5C%3Aboth%5C%3Asides%7D)
![4x+7-7=3x+7-7](https://tex.z-dn.net/?f=4x%2B7-7%3D3x%2B7-7)
![\mathrm{Simplify}](https://tex.z-dn.net/?f=%5Cmathrm%7BSimplify%7D)
![4x=3x](https://tex.z-dn.net/?f=4x%3D3x)
![\mathrm{Subtract\:}3x\mathrm{\:from\:both\:sides}](https://tex.z-dn.net/?f=%5Cmathrm%7BSubtract%5C%3A%7D3x%5Cmathrm%7B%5C%3Afrom%5C%3Aboth%5C%3Asides%7D)
![4x-3x=3x-3x](https://tex.z-dn.net/?f=4x-3x%3D3x-3x)
![\mathrm{Simplify}](https://tex.z-dn.net/?f=%5Cmathrm%7BSimplify%7D)
![x=0](https://tex.z-dn.net/?f=x%3D0)
<u>Checking the 4th option:</u>
![-3\left(2x-5\right)=15-6x](https://tex.z-dn.net/?f=-3%5Cleft%282x-5%5Cright%29%3D15-6x)
![\mathrm{Subtract\:}15\mathrm{\:from\:both\:sides}](https://tex.z-dn.net/?f=%5Cmathrm%7BSubtract%5C%3A%7D15%5Cmathrm%7B%5C%3Afrom%5C%3Aboth%5C%3Asides%7D)
![-6x+15-15=15-6x-15](https://tex.z-dn.net/?f=-6x%2B15-15%3D15-6x-15)
![\mathrm{Simplify}\](https://tex.z-dn.net/?f=%5Cmathrm%7BSimplify%7D%5C)
![-6x=-6x](https://tex.z-dn.net/?f=-6x%3D-6x)
![\mathrm{Add\:}6x\mathrm{\:to\:both\:sides}](https://tex.z-dn.net/?f=%5Cmathrm%7BAdd%5C%3A%7D6x%5Cmathrm%7B%5C%3Ato%5C%3Aboth%5C%3Asides%7D)
![-6x+6x=-6x+6x](https://tex.z-dn.net/?f=-6x%2B6x%3D-6x%2B6x)
![\mathrm{Simplify}](https://tex.z-dn.net/?f=%5Cmathrm%7BSimplify%7D)
![\mathrm{Both\:sides\:are\:equal}](https://tex.z-dn.net/?f=%5Cmathrm%7BBoth%5C%3Asides%5C%3Aare%5C%3Aequal%7D)
![\mathrm{True\:for\:all}\:x](https://tex.z-dn.net/?f=%5Cmathrm%7BTrue%5C%3Afor%5C%3Aall%7D%5C%3Ax)
Result:
Therefore, from the above calculations it is clear that, the linear equation
has no solution.
The probability of picking two blue would be 2/9 because you would use the 2 out of the 9
Let set C = {1, 2, 3, 4, 5, 6, 7, 8} and set D = {2, 4, 6, 8}.
g100num [7]
<span>1. If it is intersection then it SHOULD be included in both the sets right?
Now we know that odd numbers from 1-100 but the second set are multiples of 5 from 50-150! So we mainly need to look for common numbers which are ODD and are a MULTIPLE OF 5 BETWEEN 50 - 100!!
So
A={51,53,57,59,61......99}
B={55,60,65,70.......95} [We stop till 100 because set A has no such element]
So what is A ∩ B here?
A ∩ B = {All odd numbers and multiples of 5 between 50 - 100}
</span>
Answer:
I'd say 6.9 paces per mile.
Step-by-step explanation: