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3 years ago

What is the difference between a vigorous sport and vigorous recreation ?

Physics

1 answer:

NNADVOKAT [17]3 years ago

7 0

Answer:

Explanation:El ejercicio vigoroso previene en mayor medida el síndrome metabólico (un conjunto de enfermedades que aumentan el riesgo cardiovascular )

mientras que una reacción vigorosa se produce entre el aluminio y el gas cloro. Como consecuencia de la gran cantidad de energía liberada se producen luz y calor

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Three small children of mas 20.0 kg, 24.0 kg, and 16.0 kg, respectively, hold hands, as

olya-2409 [2.1K]

Answer:

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3 years ago

What occurs when an unstable atomic nucleus changes into other nuclei by emitting particles and energy

Klio2033 [76]

I'm not too sure but I think it's nuclear decay

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2 years ago

Three parachutists have the following masses: A: 50 kg, B: 40 kg, C: 75 kg Which one has the greatest terminal velocity?

allochka39001 [22]

Answer:

A: 50 kg

Explanation:

5 0

3 years ago

) A 1000 kg car travelling at 50 m/s slams into a 1500 kg parked truck in an inelastic manner as

solmaris [256]

(a)

KE = m v^2 / 2 = (1200 kg)(20 m/s)^2 / 2 = 240,000 J

(b)

The energy is entirely dissipated by the force of friction in the brake system.

(c)

W = delta KE = KEf - KEi = (0 - 240,000) J = -240,000 J

(d)

Fd = delta KE

F = (delta KE) / d = (-240,000 J) / (50 m) = -4800 N

The magnitude of the friction force is 4800 N.

8 0

3 years ago

A 5.50-kg object is hung from the bottom end of a vertical spring fastened to an overhead beam. The object is set into vertical

iris [78.8K]

Answer:

17.71N/m

Explanation:

The period of the spring is expressed according to the expression;

$T = 2 \pi \sqrt{\frac{m}{k} } \\$

m is the mass of the object

k is the force constant

Given

m = 5.50kg

T = 3.50s

Substitute into the formula;

$T = 2 \pi \sqrt{\frac{m}{k} } \\3.5 = 2 (3.14) \sqrt{\frac{5.5}{k} } \\3.5 = 6.28 \sqrt{\frac{5.5}{k} } \\\frac{3.5}{6.28} = \sqrt{\frac{5.5}{k} } \\0.557 = \sqrt{\frac{5.5}{k} } \\square \ both \ sides\\0.557^2 = (\sqrt{\frac{5.5}{k} })^2 \\0.3106 = \frac{5,5}{k}\\k = \frac{5.5}{0.3106}\\k = 17.71N/m$

Hence the force constant of the spring is 17.71N/m

4 0

3 years ago