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Lady_Fox [76]
3 years ago
13

What is the weight of the body under the influence of a force of 10N reaches a speed of 1.5 m / s in 3s?

Physics
1 answer:
MariettaO [177]3 years ago
8 0

Answer:

Explanation:

F=ma

F=10N

A=v-u upon t

=1.5-0 upon 3

=0.5m per second squared

Then do force divided by. Accelaration and multiply by gravity.

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A worker on the roof of a house drops his 0.46 kg hammer, which slides down the roof at constant speed of 9.88 m/s. The roof mak
nekit [7.7K]

Answer:

The horizontal distance travelled in that time lapse is 12.94 m

Explanation:

In order to solve this problem, we'll need:

  1. The horizontal speed
  2. the time the hammer takes to fall from the roof to the ground

At the lowest point of the roof, the hammer has a 9.88 m/s speed that makes an angle of 27° with the horizontal, so we can calculate the horizontal and vertical speed with trigonometry. If we take right as x positive and down as y positive we get

v_{x}=v*cos(27)=9.88 m/s *cos(27)=8.80 m/s \\v_{y}=v*sen(27)=9.88 m/s *sen(27)=4.49 m/s

Now, we make two movement equation as we have a URM (no acceleration) in x and an ARM (gravity as acceleration) in y. We will wisely pick the lowest point of the roof as the origin of coordinates

x(t)=8.8 m/s *t

y(t)=4.49m/s*t+\frac{1}{2}*9.8m/s^{2}*t^{2}

Now we calculate the time the hammer takes to get to the floor

17.1m=4.49m/s*t+\frac{1}{2}*9.8m/s^{2}*t^{2}\\t=1.47s or t=-2.38s

Now, we keep the positive time result and calculate the horizontal distance travelled

x(1.47s)=8.8m/s*1.47s=12.94m

3 0
3 years ago
How did ALS impact Stephen Hawking?
olga nikolaevna [1]

Answer:

Professor Hawking had just turned 21 when he was diagnosed with a very rare slow-progressing form of ALS, a form of motor neurone disease (MND). He was at the end of his time at Oxford when he started to notice early signs of his disease. He was getting more clumsy and fell over several times without knowing why.

Explanation:

none

6 0
3 years ago
Varg sees a spring that has a spring constant of 4 N/m that is stretched 5 m. He stretches the spring an additional 5 m. Conside
AysviL [449]

Answer:

Elastic potential energy, E = 200 J

Explanation:

It is given that,

Spring constant, K = 4 N/m

initial stretching in the spring, x = 5 m

Finally, it is stretched an additional 5 m i.e. x' = 5 m        

Let E is the elastic energy in the spring after Varg stretches the spring. it is given by :

E=\dfrac{1}{2}k(x+x')^2

E=\dfrac{1}{2}\times 4\times (10)^2

E = 200 J

So, the elastic energy in the spring after Varg stretches the spring is 200 J. hence, this is the required solution.

8 0
3 years ago
Read 2 more answers
Similarity between heat and temperature
pentagon [3]
Heat is a temperature and temperature has many factors such and cold, warm, and hot.
7 0
3 years ago
Select the correct answer.
VladimirAG [237]

Answer:

It's effective temperature.

Explanation:

8 0
3 years ago
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