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ycow [4]
3 years ago
14

Composition of Dry AirGas Percent by Volume (%)Nitrogen (N2) 78Oxygen (O2) 21Argon (Ar) 0.9Carbon dioxide (CO2) 0.04 What volume

of air contains 12.3 g of oxygen gas at 273 K and 1.00 atm
Chemistry
1 answer:
Minchanka [31]3 years ago
5 0

Answer:

40.95 L

Explanation:

We'll begin by calculating the number of mole in 12.3 g of O₂. This can be obtained as follow:

Mass of O₂ = 12.3 g

Molar mass of O₂ = 16 × 2 = 32 g/mol

Mole of O₂ =?

Mole = mass / Molar mass

Mole of O₂ = 12.3 / 32

Mole of O₂ = 0.384 mole

Next, we shall determine the volume occupied by 0.384 mole of O₂. This can be obtained as follow:

Number of mole (n) of O₂ = 0.384 mole

Pressure (P) = 1 atm

Temperature (T) = 273 K

Gas constant (R) = 0.0821 atm.L/Kmol

Volume (V) of O₂ =?

PV = nRT

1 × V = 0.384 × 0.0821 × 273

V = 0.384 × 0.0821 × 273

V = 8.6 L

Thus, the volume of O₂ is 8.6 L

Finally, we shall determine the volume of air that contains 8.6 L of O₂. This can be obtained as follow:

Volume of O₂ = 8.6 L

Percentage of O₂ in air = 21%

Volume of air =?

Percentage of O₂ = Vol of O₂ / Vol of air × 100

21% = 8.6 / Vol of air

21 / 100 = 8.6 / Vol of air

Cross multiply

21 × Vol of air = 100 × 8.6

21 × Vol of air = 860

Divide both side by 21

Volume of air = 860 / 21

Volume of air = 40.95 L

Therefore, the volume of air is 40.95 L.

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200g of solution of magnesium
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<h3>What is the relation between mass & moles?</h3>

Relation between the mass and moles of any substance will be represented as:

n = W/M, where

  • W = given mass
  • M = molar mass

Moles of MgCl₂ = 200g / 95g/mol = 2.1mol

Moles of NaOH = 20g / 0.5mol

Given chemical reaction is:

MgCl₂ + 2NaOH → 2NaCl + Mg(OH)₂

From the stoichiometry of the reaction it is clear that

  • 1 mole of MgCl₂ = reacts with 2 moles of NaOH
  • 0.5 mole of NaOH = reacts with (1/2)(0.5)=0.25 moles of MgCl₂

Mass of reacted MgCl₂ = (0.25mol)(95g/mol) = 23.75g

Percent by mass of MgCl₂ in the given solution mixture will be calculated as:

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In the above reaction we obtain NaCl as a solid, and MgCl₂ is the limiting reagent in it, from which 2 moles of NaCl is produced means

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Mass of NaCl = (0.5mol)(58.5g/mol) = 29.25g

Hence, mass of reacted MgCl₂ is 23.75g, percent by mass of solution magnesium chloride is 90.9% and mass of the obtained solid is 29.25g.

To know more about mass & moles, visit the below link:

brainly.com/question/20838755

#SPJ1

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