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Whitepunk [10]
3 years ago
11

What is the limiting reactant in the following reaction if 1.63g of NH3 is reacted with 3.47g of Cl2 ?

Chemistry
1 answer:
Maurinko [17]3 years ago
8 0

Answer:

B

Explanation:

you will have to find the number of moles for each 4Nh3 and 3cl2

4NH3                        

m= 1.63

mr= 14+1x3= 17

n.of moles = 1.63/17=0.09588

3CL2

m=3.47

mr=35.5x2=71

nof moles = 3.47/71= 0.04887

after getting the number of moles you will divide your answer by its ratio

4NH3                                                 3CL2

0.09588/4=0.02397                         0.04887/3= 0.0133

the smaller number will be the limiting reagent while the bigger number is the excess reagent

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