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kirza4 [7]
2 years ago
15

PLS ANSWER I WILL GIVE BRAINLY TO First!!!

Chemistry
1 answer:
Korolek [52]2 years ago
6 0

Answer:

if I tell the ans u won't give me brainly

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Find the relative molecular mass of hydrated iron (II) sulphate FeSO4.7H2O
Pepsi [2]

Answer:

the relative molecular mass of hydrated iron (II) sulfate FeSO4.7H2O is 278.02

Explanation:

5 0
2 years ago
I need help with this, please :00000
mojhsa [17]

theoretical yield of the reaction is 121.38 g of NH₃ (ammonia)

limiting reactant is N₂ (nitrogen)

excess reactant is H₂ (hydrogen)

Explanation:

We have the following chemical reaction:

N₂ + 3 H₂ → 2 NH₃

Now we calculate the number of moles of each reactant:

number of moles = mass / molar weight

number of moles of N₂ = 100 / 28 = 3.57 moles

number of moles of H₂ = 100 / 2 = 50 moles

From the chemical reaction we see that 3 moles of H₂ are reacting with 1 moles of N₂, so 50 moles of H₂ are reacting with 16.66 moles of N₂ but we only have 3.57 moles of  N₂ available, so the limiting reactant will be N₂ and the excess reactant will be H₂.

Knowing the chemical reaction and the limiting reactant we devise the following reasoning:

if          1 mole of N₂ produce 2 moles of NH₃

then    3.57 moles of N₂ produce X moles of NH₃

X = (3.57 × 2) / 1 = 7.14 moles of NH₃

mass = number of moles × molar weight

mass of NH₃ = 7.14 × 17 = 121.38 g

theoretical yield of the reaction is 121.38 g of NH₃

Learn more about:

limiting reactant

brainly.com/question/13979150

#learnwithBrainly

4 0
3 years ago
The Transition Elements can be divided into two types. List each type.
jenyasd209 [6]
Main group elements
transition metals
lanthanides
actindes.
7 0
3 years ago
The chlorination of the iron (III) ion is an endothermic reaction.
snow_tiger [21]

Answer:

d

Explanation:

5 0
3 years ago
What is the percentage by mass of sulphur in Al2(SO4)3[A12SO4 =<br>342g/mol, S = 32]​
valentinak56 [21]

Answer: The percentage by mass of sulphur in Al_2(SO_4)_3 is 9.36%

Explanation:

Mass percent of an element is the ratio of mass of that element by the total mass expressed in terms of percentage.

{\text {Mass percentage}}=\frac{\text {mass of sulphur}}{\text {Total mass}}\times 100\%

Given: mass of sulphur = 32 g/mol

mass of Al_2(SO_4)_3 = 342 g/mol

Putting in the values we get:

{\text {Mass percentage}}=\frac{32g/mol}{342g/mol}\times 100\%=9.36\%

The percentage by mass of sulphur in Al_2(SO_4)_3 is 9.36%

4 0
3 years ago
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