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mr Goodwill [35]
2 years ago
8

Balance the following chemical equation: H3PO4 + HCl → PC15 + H20

Physics
1 answer:
kipiarov [429]2 years ago
3 0

Answer:

H3PO4 + 5HCl → PCl5 + 4H2O

Explanation:

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How is the capacitance of a capacitor related to the charge stored on the capacitor and the potential difference across the capa
tatuchka [14]

Answer:

Capacitance is the ratio of the charge to the potential difference. How is the charge stored on a capacitor related to the capacitance of the capacitor and the potential difference across the capacitor? The charge equals the product of the capacitance and the potential difference.

Explanation:

Hope this helps

6 0
2 years ago
Suppose you dissolve 12.8 g of one substance in 11 g of another. Is this reasonable? Explain
RUDIKE [14]

Answer:

No, its not reasonable.

Explanation:

The substance that is to be dissolved is known as solute. The substance that is dissolving is known as solvent.

The amount of solvent  in the mixture should be greater than that of solute.

Suppose we are taking a solvent in a beaker and we are continuously adding solute in it. Initially the solute dissolve quickly. At some point the solute stops dissolving in the solvent. This is known as saturation point of the solvent. After saturation point if solute is added further it does not dissolve in the solvent.

So, its not possible to dissolve 12.8 g of one substance in 11 g of another.

5 0
3 years ago
The transfer of energy through matter by the direct contact of particles is called __________.
kaheart [24]
The transfer of energy through matter by the direct contact of particles is called conduction
3 0
3 years ago
A 62-kg person jumps from a window to a fire net 20.0 m directly below, which stretches the net 1.4 m. Assume that the net behav
gayaneshka [121]

Answer:

a) x = 0.098

b) x = 2.72 m

Explanation:

(a) To find the stretch of the fire net when the same person is lying in it, you can assume that the net is like a spring with constant spring k. It is necessary to find k.

When the person is falling down he acquires a kinetic energy K, this energy is equal to the elastic potential energy of the net when it is max stretched.

Then, you have:

K=U\\\\\frac{1}{2}mv^2=\frac{1}{2}kx^2        (1)

m: mass of the person = 62kg

k: spring constant = ?

v: velocity of the person just when he touches the fire net = ?

x: elongation of the fire net = 1.4 m

Before the calculation of the spring constant, you calculate the final velocity of the person by using the following formula:

v^2=v_o^2+2gy

vo: initial velocity = 0 m/s

g: gravitational acceleration = 9.8 m/s^2

y: height from the person jumps = 20.0m

v=\sqrt{2gy}=\sqrt{2(9.8m/s^2)(20.0m)}=14\frac{m}{s}

With this value you can find the spring constant k from the equation (1):

mv^2=kx^2\\\\k=\frac{mv^2}{x^2}=\frac{(62kg)(14m/s)^2}{(1.4m)^2}=6200\frac{N}{m}

When the person is lying on the fire net the weight of the person is equal to the elastic force of the fire net:

W=F_e\\\\mg=kx

you solve the last expression for x:

x=\frac{mg}{k}=\frac{(62kg)(9.8m/s^2)}{6200N/m}=0.098m

When the person is lying on the fire net the elongation of the fire net is 0.098m

b) To find how much would the net stretch, If the person jumps from 38 m, you first calculate the final velocity of the person again:

v=\sqrt{2gy}=\sqrt{2(9.8m/s^2)(38m)}=27.29\frac{m}{s}

Next, you calculate x from the equation (1):

x=\sqrt{\frac{mv^2}{k}}=\sqrt{\frac{(62kg)(27.29m/s)^2}{6200N/m}}\\\\x=2.72m

The net fire is stretched 2.72 m

5 0
3 years ago
A standard inverting op-amp circuit has an R1 of 10 kΩ and an Rf of 220 kΩ. If the offset current is 100 nA the output offset vo
kiruha [24]

Answer:

The value is  V_{os} = 0.001 \  V

Explanation:

From the question we are told that

     The circuit resistance is  R_1 =  10 \ k \Omega

     The feedback resistance  is  R_f =  220 \ k \Omega

      The offset current is  I_{os } = 100 \  nA  =  100 * 1)^{-9} \ A

Generally the offset voltage is mathematically reparented as

           V_{os} =  R_f * I_{os}

=>        V_{os} = 10 *10^{3}*  100 *10^{-9}

=>        V_{os} = 0.001 \  V

6 0
3 years ago
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