Answer:
The distance traveled by the faster car when it is 15 mins ahead of the slower car is 165 miles.
Explanation:
Given;
speed of the faster car, v₁ = 60 mi/h
speed of the slower car, v₂ = 55 mi/h
Let the distance traveled by the faster car when it is 15 mins ahead of the slower car = x miles
Note: divide 15 mins by 60 to convert to hours for consistency in the units.
Therefore, the distance traveled by the faster car when it is 15 mins ahead of the slower car is 165 miles.
Answer:
a) the pattern is bright, b) y = 8.25 mm, c) the distance increases with the wavelength increases
Explanation:
This is a team building exercise to perform interference experiments, where the separation of the slits is d = 1 m = 1 10⁻³ m and the distance to the screen L = 1.5 m
Constructive interference occurs when the path difference is equal to an integer number of wavelengths
d sin θ = m λ
a) The center of the two-ray pattern has the same length so the intensity is MAXIMUM, that is, the pattern is bright
b) to find the distance let's use trigonometry
tan θ= y / L
tan θ =sin θ/cos θ= sin θ
because the angles are small
we substitute
y =
let's calculate
y = 10 550 10⁻⁹ 1.5 / 1 10⁻³
y = 8.25 10⁻³ m
c) for this part the incident light must be white or polychrome light
let's find the distance (y) for some colors, in the first order
Violet λ = 400
y = 1 400 10⁻⁹ 1.5 / 1 10⁻³
y = 6 10⁻⁴ m
green λ = 500 nm
y = 1 500 10⁻⁹ 1.5 / 1 10⁻³
y = 7.5 10⁻⁴ m
yellow λ = 600 nm
y = 1 600 10⁻⁹ 1.5 / 1.10⁻³
y = 9 10⁻⁴ m
lam λ = 700 nm
y = 1 700 10⁻⁹ 1.5 / 1. 10⁻³
y = 1.05 10⁻³ m
violet, green, orange, red
the distance increases with the wavelength increases
d) To find the wavelength we must measure the distance y from the center of the slit for various interference orders and using the equation we can find the wavelength of rationality