Answer:
that results in an alcohol and a carboxylic acid.
Explanation:
Saponification is a chemical reaction process of alkaline hydrolysis of esters(R'COOR group) by which soap is obtained.
For Example, when a base such as sodium hydroxide [NaOH] is used to hydrolyze an ester, the products are a carboxylate salt and an alcohol. Because soaps are prepared by the alkaline hydrolysis of fats and oils.
In a saponification reaction, alkaline hydrolysis of fats and oils with sodium hydroxide yields propane-1,2,3-triol and the corresponding sodium salts of the component fatty acids.
i.e Fat or oil + caustic alkali ⇒ Soap + propane-1,2,3-triol
As a specific example, ethyl acetate and NaOH react to form sodium acetate and ethanol:
The reaction goes to completion in the image below:
Answer: The value of Keq for the reaction expressed in scientific notation is 
Explanation:
Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios.
For the given chemical reaction:
The expression for 
is written as:
![K_{eq}=\frac{[NO]^2\times [Cl_2]}{[NOCl]^2}](https://tex.z-dn.net/?f=K_%7Beq%7D%3D%5Cfrac%7B%5BNO%5D%5E2%5Ctimes%20%5BCl_2%5D%7D%7B%5BNOCl%5D%5E2%7D)
The value of Keq for the reaction expressed in scientific notation is
Hi there.
Alkali metals are known as the group 1 elements.
When we know this, we just have to look to group 1 of the periodic table.
Rb (Rubidium) is in group 1; it is classified as an alkali metal.
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Answer:
The wavelength the student should use is 700 nm.
Explanation:
Attached below you can find the diagram I found for this question elsewhere.
Because the idea is to minimize the interference of the Co⁺²(aq) species, we should <u>choose a wavelength in which its absorbance is minimum</u>.
At 400 nm Co⁺²(aq) shows no absorbance, however neither does Cu⁺²(aq). While at 700 nm Co⁺²(aq) shows no absorbance and Cu⁺²(aq) does.
