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3 years ago

14

Look at the graph below. Which statement is TRUE based on the graph of an egg drop experiment? A.The egg is not accelerating. B.

The speed of the egg is constant. C.The egg is accelerating. D.The speed of the egg is decreasing.

2 answers:

lord [1]3 years ago

8 0

C is the right answer

belka [17]3 years ago

3 0

I'm pretty sure your correct answer is D

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A flask contains an equal mixture of oxygen and argon. Which of the following statements is true about the effusion of the gases

frozen [14]

Given that the pressure, temperature and area of effusion is constant, the rate of effusion is inversely proportional to the square root of the molecular mass of the gas.
Mr Oxygen = 32
Mr Argon = 40
Effusion Oxygen = 1/√32
Effusion Argon = 1/√40
Effusion Oxygen / Effusion Argon = √(40) / √(32)
=√(40/32) = √(5/4) = 1.19
Thus, Oxygen will effuse 1.19 times faster than Argon. The second option is correct.

8 0

3 years ago

An acetate buffer solution is prepared by combining 50. mL of 0.20 M acetic acid,

natima [27]

Answer:

The answer is "Option B".

Explanation:

$\to CH_3COOH + NaOH \longleftrightarrow CH_3COONa + H_2O\\\\\to CH_3COONa + NaOH\longleftrightarrow CH3COONa\\\\\therefore \ mol\ NaOH = (5 \ E-3\ L)\times(0.10 \ \frac{mol}{L}) = 5 \ E-4\ mol\\\\$

$\to mol\ CH_3COOH = (0.05 \ L)\times(0.20 \frac{mol}{L}) = 0.01 \ mol\\\\\to C \ CH_3COOH = \frac{(0.01 \ mol - 5 \ E-4\ mol) }{(0.105 \ L)}\\\\\to C \ CH_3COOH = 0.0905 \ M\\\\\therefore \ mol \ CH_3COONa = (0.05\ L )\times (0.20 \ \frac{mol}{L}) = 0.01 \ mol\\\\$

$\to C \ CH_3COONa = \frac{(0.01\ mol + 5 \ E-4\ mol)}{(0.105\ L )}\\\\\to C \ CH_3COONa = 0.1 \ M\\\\\therefore Ka = ([H_3O^{+}]\times \frac{(0.1 + [H_3O^+]))}{(0.0905 - [H_3O^+])} = 1.75\ E-5\\\\\to 0.1[H_3O^+] + [H_3O^+]^2 = (1.75 E-5)\times (0.0905 - [H_3O^+])\\\\$

$\to [H_3O^+]^2 \ 0.1[H_3O^+] = 1.584\ E-6 - 1.75\ E-5[H_3O^+]\\\\\to [H_3O^+]^2 + 0.1000175[H_3O^+] - 1.584 \ E-6 = 0\\\\\to [H_3O^+] = 1.5835\ E-5 \ M\\\\\therefore pH = - \log [H_3O^+]\\\\\to pH = - \log (1.5835 \ E-5)\\\\ \to pH = 4.8004 > 4.7$

5 0

2 years ago

One mole of an ideal gas doubles its volume in a reversible isothermal expansion. (a) What is the change in entropy of the gas?

Andre45 [30]

Explanation:

The given data is as follows.

n = 1 mol, $V_{f} = 2V_{i}$

Q = 1500 J, R = 8.314 J/mol k

(a) $\Delta S = \frac{dQ}{dT}$

And, according to the first law of thermodynamics

$\Delta E_{int} = Q - W$

And, in an isothermal process the change in internal energy of the gas is zero.

Hence, 0 = Q - W

or, W = Q

Expression for work done in an isothermal process is as follows.

W = $nRT ln \frac{V_{f}}{V_{i}}$

As W = Q, Hence expression for Q will also be given as follows.

Q = $nRT ln \frac{V_{f}}{V_{i}}$

Now,

$\Delta S = \frac{nRT ln \frac{V_{f}}{V_{i}}}{T}$

[/tex]\Delta S = nR ln \frac{V_{f}}{V_{i}}[/tex]

= $nR ln \frac{2V_{i}}{V_{i}}$

= nR ln 2

= $1 \times 8.314 \times 0.693$

= 5.76 J/K

Therefore, change in entropy is 5.76 J/K.

(b) As, Q = $nRT ln \frac{V_{f}}{V_{i}}$

= $nRT ln \frac{2V_{i}}{V_{i}}$

= nRT ln 2

T = $\frac{Q}{nR ln 2}$

= $\frac{1500}{1 \times 8.314 ln 2}$

= 260.4 K

Therefore, temperature of the gas is 260.4 K.

7 0

2 years ago

Is smelting a chemical or physical process?

nydimaria [60]

Smelting is chemical because you are refining the ore. Also when you heat substances, there is a chance you will decompose some compounds in the process.

7 0

3 years ago

What happens to the density of earth's interior as you travel from the crust to the core

lara31 [8.8K]

As you go deeper into, the pressure rises. Density is defined as mass/volume. Because of pressure, the layers beneath us become densely packed.

6 0

2 years ago