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jek_recluse [69]
3 years ago
7

Name this compound Cr2(CO3)3

Chemistry
1 answer:
kiruha [24]3 years ago
5 0

Answer:

Molecular Weight

Explanation:

Chromium(III) Carbonate Cr2(CO3)3 Molecular Weight -- EndMemo.

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If the first reaction used 0.5 g of copper then how many grams of copper will be produced in the last reaction?
Nadya [2.5K]
Insufficient Information
7 0
3 years ago
Which equation represents a redox reaction?
labwork [276]

Answer:

D. 2NaBr + Cl_2\rightarrow 2NaCl + Br_2

Explanation:

Hello!

In this case, for the given set of chemical reactions, it is possible to infer that D. is a categorized as redox due to the following:

Since both chlorine and bromine remain as diatomic gases, their oxidation states in such a form is 0, but as anions with lithium cations they have a charge of - according to the following reaction and half-reactions:

2NaBr + Cl_2\rightarrow 2NaCl + Br_2

Cl_2^0+2e^-\rightarrow 2Cl ^-\\\\2Br^- \rightarrow  Br_2^0+2e^-

Unlike the other reactions whereas no change in the oxidation states is evidenced.

6 0
3 years ago
Read 2 more answers
Calculate the number of joules needed to change the temperature of 40.0 g of water from 33.0 degree c to 43.0 degree c
nikdorinn [45]

Answer:

c

Explanation:

7 0
2 years ago
Vinegar is a solution of acetic acid, CH3COOH, dissolved in water. A 5.54-g sample of vinegar was neutralized by 30.10 mL of 0.1
tekilochka [14]

Answer:

3.26 % of vinegar is acetic acid

Explanation:

Step 1: Data given

Mass of the sample = 5.54 grams

Volume of NaOH = 30.10 mL

Molarity of NaOH = 0.100M

Step 2: The balanced equation

CH3COOH + NaOH → CH3COONa + H2O

Step 3: Calculate moles NaOH

Moles NaOH = volume * molarity

Moles NaOH = 0.03010 L * 0.100M

Moles NaOH = 0.00301 moles NaOH

Step 4: Calculate moles CH3COOH

For 1 mol NaOH we need 1 mol CH3COOH

For 0.00301 moles NaOH we nee 0.00301 moles CH3COOH

Step 5: Calculate mass CH3COOH

Mass CH3COOH = moles CH3COOH * molar mass CH3COOH

Mass CH3COOH = 0.00301 moles * 60.05 g/mol

Mass CH3COOH = 0.1808 grams

Step 6: Calculate percent by weight of acetic acid

Mass % = ( 0.1808 / 5.54 ) *100%

Mass % = 3.26 %

3.26 % of vinegar is acetic acid

7 0
3 years ago
An unknown compound has a percent composition of 52.10% potassium, 15.8% carbon, and 32.1% oxygen. The molar mass of the compoun
lianna [129]
To determine the empirical formula and the molecular formula of the compound, we assume a basis of the compound of 100 g. We do as follows:

       Mass              Moles                     
K    52.10     52.10/39.10 = 1.33         1.33/1.32 ≈ 1
C    15.8       15.8/12         = 1.32         1.32/1.32 ≈ 1
O     32.1      32.1 / 16       =  2.01        2.01/1.32 ≈ 1.5

The empirical formula would most likely be KCO.
The molecular formula would be K2C2O3.
4 0
3 years ago
Read 2 more answers
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