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Travka [436]
3 years ago
13

Amelia's water bottle holds 4 pints, 2 cups. How many cups does Amelia's water bottle hold? Note: 1 pint = 2 cups​

Mathematics
1 answer:
ivann1987 [24]3 years ago
3 0

Answer:

10 cups

Step-by-step explanation:

4x2=8. 8+ the 2 cups in the beginning would be 10 cups.

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1. State if each scenario involves a permutation or a combination. Then find the number of possibilities:(a) Castel and Joe are
BaLLatris [955]

Answer:

a) This is a permutation, there are 210 ways to do it

b) This is a permutation with 6 possibilities

c) This is a combination with a total of 1081575 possibilities

Step-by-step explanation:

a) Here the order does matter bacause it is not the same that they go to France in the weak trip than they go there for 2 days, as a result, this scenario is a permutation.

You need to pick 3 countries from a total of 7, but the order matters, so the total amount of ways to do this is

{7 \choose 3} * 3! = \frac{7!}{(7-3)!} = 210

b) Here each permutation of 123 will give you a possible (and a different one from the others) lock-combination, so this is again a permutation.

The total amount of ways we have to do the selectio of the lock-combination is the total amount of permutations of a set of 3 elements, in other words, it is 3! = 6.

c) If you only cares about who advances to the finals, then the order doesnt matter here, you just want 8 people out of the 25 available. This is therefore a combination, and the total amount of possible cases are

{25 \choos 8} = 1081575 .

5 0
3 years ago
What are the factors of m2 – 6m + 6m – 36? (m – 2)(m + 18) (m – 3)(m + 3) (m – 4)(m + 9) (m – 6)(m + 6)
77julia77 [94]
<span>(m – 6)(m + 6) is the answer.
If you distribute them, you'll get </span><span>m^2 - 36</span>
3 0
3 years ago
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How is the measurement 0.000065 cm written in scientific notation?
omeli [17]
6.5*10^-5 is the answer if tou have to move the decimal to the right is is negative and then count how many spaces

4 0
3 years ago
"(b) use part (a) to find a power series for f(x) = 1 (4 + x)3 ."
Firdavs [7]
Assuming

f(x)=\dfrac1{(4+x)^3}

Recall that for |x|,

\displaystyle\sum_{n\ge0}x^n=\frac1{1-x}

Denote the above by s(x). Then

s'(x)=\displaystyle\sum_{n\ge1}nx^{n-1}=\frac1{(1-x)^2}
s''(x)=\displaystyle\sum_{n\ge2}n(n-1)x^{n-2}=\frac2{(1-x)^3}

Now,

\dfrac1{(4+x)^3}=\dfrac1{4^3}\dfrac1{\left(1-\left(-\frac x4\right)\right)^3}=\dfrac1{2^7}\dfrac2{\left(1-\left(-\frac x4\right)\right)^3}

which means we have

f(x)=\dfrac1{2^7}s''(x)=\dfrac1{128}\displaystyle\sum_{n\ge2}n(n-1)\left(-\frac x4\right)^{n-2}

which is valid for \left|-\dfrac x4\right|, or |x|.
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I got 100% on my test today yay <3
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