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3 years ago

I need help on number 2 and 3

Physics

1 answer:

irinina [24]3 years ago

4 0

For 2 draw the molucules very close together. because in soilds the molucules are VERY close to gether.

and for 3 Draw them with a lot of space apart from each other. Molucules move freely and openly in air and space.

Hope this helps! Please mark as brainliest! Thanks!! :D

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Objects in space that are moving at a constant velocity in a straight line ___________.

nikdorinn [45]

The best answer is A) <span>keep moving at a constant velocity until some forces act on them

As the man you're probably tired of hearing about said:

"Every object persists in its state of rest or in uniform motion in a straight line unless a new force acts upon it"
This is Isaac Newton's 1st law of motion, or the law of inertia.

Put more simply, objects in motion tend to stay in motion, and tend the maintain the same velocity (direction and speed) and objects at rest tend to stay at rest. </span>

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3 years ago

Read 2 more answers

The Acorn Insurance Company charges $3.50 for each unit of coverage under a block of 1-year term life insurance policies. The an

ICE Princess25 [194]

Answer:

$175

Explanation:

Insurance premium is expressed as a rate $1000

($3.50 per $1000)

Therefore;

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3 years ago

A pear hangs in a tree at a height of 1.8 m. The pear has a mass of 0.2 kg. The pear falls out of the tree and lands on the grou

TiliK225 [7]

a) PE=mgh=0.2*9.8*1.2=2.352 J

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3 years ago

A 4.3-kg block slides down an inclined plane that makes an angle of 30° with the horizontal. Starting from rest, the block slide

-BARSIC- [3]

Answer:

0.56

Explanation:

Let the coefficient of friction is μ.

m = 4.3 kg, θ = 30 degree, initial velocity, u = 0, s = 2.7 m, t = 5.8 s

By the free body diagram,

Normal reaction, N = mg Cosθ = 4.3 x 9.8 x Cos 30 = 36.49 N

Friction force, f = μ N = 36.49 μ

Net force acting on the block,

Fnet = mg Sinθ - f = 4.3 x 9.8 x Sin 30 - 36.49 μ

Fnet = 21.07 - 36.49μ

Net acceleartion, a = Fnet / m

a = (21.07 - 36.49μ) / 4.3

use second equation of motion

s = ut + 1/2 a t^2

2.7 = 0 + 1/2 x (21.07 - 36.49μ) x 5.8 x 5.8 / 4.3

By solving we get

μ = 0.56

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3 years ago

A hollow cylinder with an inner radius of 4.0 mm and an outer radius of 30 mm conducts a 3.0-Acurrent flowing parallel to the ax

Kryger [21]

Answer:

the magnitude of the magnetic field is 0.45 mT

Explanation:

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3 years ago