Answer:
19.33°C
Explanation:
To find the value of T you use the following formula:
v: speed of sound
To calculate v you use:
λ: wavelength = 0.651m
f: = 545Hz
by replacing :
Finally, by replacing in the first formula you obtain:
T = 19.33°C
Answer:
300 meters per second. That's equal to about 670 miles per hour.
Explanation:
Not only are air particles incredibly small, they are always moving. And they move fast. At room temperature, they are going about 300 meters per second. That's equal to about 670 miles per hour.
Answer:
<h3><em>
28.01m/s.</em></h3>
Explanation:
Given maximum height reached by the ball as H = 40 metres
Since the ball rises straight up when hit by a ball, then the angle of launch will be perpendicular to the ground and that is 90°.
To determine the upward speed of the ball in meters per second after it got struck by the bat, we will use the formula for calculating the maximum height according to projectile motion;
Maximum Height H = 
where;
u is the speed of the ball
is the angle of launch
g is the acceleration due to gravity = 9.81m/s²
Substituting the given parameters into the formula;
<em>Hence the upward speed of the ball in meters per second after it got struck by the bat is 28.01m/s.</em>
7. First write down all the known variables while separating the values for each direction:
x-direction:
vix = 20m/s
vfx = 20m/s
x = 39.2m
y-direction:
viy = 0m/s
ay = -9.8m/s^2
y = ?
Based on the knowns, the first step is to calculate the time of flight from the x-direction as it will be the same as value for the y-direction. Find the correct kinematic equation to do so:
x = (1/2)(vix+vfx)t
(39.2) = (1/2)(20+20)t
1.96s = t
Now that we have the time of flight, we can use the kinematic equation that will relate the known variables in the y-direction:
y = viy*t + (1/2)ay*t^2
y = (0)(1.96) + (1/2)(-9.8)(1.96)^2
y = -18.82m (Value is negative because gravity constant was negative. It is the height reference that from the top of the building down, which is why it is negative. The sign can be ignored for this question.)
8. First write down all the known variables while separating the values for each direction:
x-direction:
x = 12m
vfx = 0m/s
vix = ?
y-direction:
y1 = 1.2m
y2 = 0.6m
viy = 0m/s;
ay = -9.8m/s^2
First find time in the y-direction as it would be the same value for the x-direction.
(y2 - y1) = viy*t + (1/2)ay*t^2
(-0.6) = (0)t + (1/2)(-9.8)t^2
t = 0.35s
Now that we have the time of flight, we can use the kinematic equation that will relate the known variables in the x-direction:
x = (1/2)(vix+vfx)t
(12) = (1/2)(vix+(0))(0.35)
68.6m/s = vix
X=r-p. Maybe I don't understand, but I am assuming that you need to isolate for X? you simply subtract p from both sides.<span />
