Answer:
heat rate= 1281W
length = 15.8m
Explanation:
we have this data to answer this question with
Tmi = 85 degrees
Tmo = 35 degrees
Ts = 25 dgrees
flow rate = 25 degrees
using engine oil property from table a-5
Tm = Tmo - TMi/2 = 333k
u =0.522x10⁻²
k = 0.26
pr = 51.3
cp = 2562 J/kg.k
mcp(Tmo-Tmi) =
0.01 x 2562(35-85)
= 1281 W
we find the change in Tim
= [(35-25)-(85-25)]/ln[(35-25)/(85-25)]
= -50/ln0.167
= -50/-1.78976
= 27.9°c
we finf the required reynold number
4x0.01/πx0.003x0.522x10⁻²
= 0.04/0.00004921
= 812.8
= 813
we find approximate correlation
NuD = hd/k
NuD = 3.66
3.66 = 0.003D/0.26
cross multiply
0.003D = 3.66x0.26
D = 3.66x0.26/0.003
= 317.2
As = 1281/317x27.9
= 0.145
As = πDL
L = As/πD
= 0.145/π0.003
= 0.145/0.009429
L = 15.378
Answer:
i think d maybe correct me if im wrong
Explanation:
Answer:
1514g of CO₂ reacted
Explanation:
Based on the reaction:
2CO₂ + 43.9kJ → 2CO + O₂
<em>2 moles of carbon dioxide require 43.9kJ of energy to produce 2 moles of carbon monoxide and 1 mole of oxygen</em>
<em />
To solve this question, we must convert the 755kJ of energy to moles of carbon dioxide that reacts and to find the mass as follows:
755kJ * (2 moles CO₂ / 43.9kJ) =34.4 moles of CO₂ are produced
<em>Mass CO₂: Molar mass: 44.01g/mol</em>
34.4 moles CO₂ * (44.01g / mol) =
<h3>1514g of CO₂ reacted</h3>
The oxidation number of chromium (Cr) in CrO₂, Cr₂O₇²⁻ and Cr₂(SO₄)₃³⁻ is +4, +6 and +1.5 respectively.
<h3>What is oxidation number?</h3>
Oxidation number of any compound gives idea about the number of exchangeable electrons from the outer most shell of an atom.
Let the oxidation state of chromium is x and charge on the whole molecule is zero, so it will be calculated as:
x + 2(-2) = 0
x - 4 = 0
x = +4
Let the oxidation state of chromium is x and charge on the whole molecule is -2, so it will be calculated as:
2x + 7(-2) = -2
2x - 14 = -2
2x = 12
x = +6
Let the oxidation state of chromium is x and charge on the whole molecule is -3, so it will be calculated as:
2x + 3(-2) = -3
2x - 6 = -3
2x = 3
x = +1.5 (which is impossible)
Hence oxidation state of chromium atom in CrO₂, Cr₂O₇²⁻ and Cr₂(SO₄)₃³⁻ is +4, +6 and +1.5 respectively.
To know more about oxidation state, visit the below link:
brainly.com/question/8990767
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