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Arlecino [84]
3 years ago
12

What is the oxidation number of manganese (Mn) in potassium permanganate (KMnO4)?

Chemistry
2 answers:
irina [24]3 years ago
8 0

Answer:

+7

Explanation:

Within every molecule, there is always an oxidation number assigned to every individual atom within the molecule. Hydrogen will always have an oxidation number of +1 (because it only has one electron to give, and when it gives that electron, it has a charge of +1).

Elements in group 1 always have an oxidation number of +1, and elements in group 16 always have an oxidation number of -2. Using this information we can calculate the oxidation number of Mn in the molecule KMnO₄.

Overall the molecule is neutral, so all the oxidation numbers would add up to zero:

K + Mn + O₄ = 0

(+1) + Mn + 4(-2) = 0

(+1) + Mn + (-8) = 0

Mn + (-7) = 0

Mn = +7

andrezito [222]3 years ago
7 0

What is the oxidation number of manganese (Mn) in potassium permanganate (KMnO4)?

+3
+5
+6
+7

The oxidation number of manganese (Mn) in potassium permanganate (KMnO4) is +5. 

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Answer:

31.31× 10²³ number of Cl⁻ are present in 2.6 moles of CaCl₂ .

Explanation:

Given data:

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The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

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2.6×2 = 5.2 moles

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