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noname [10]
3 years ago
12

61 Cu 29 Write the complete nuclear equations for alpha absorption

Chemistry
1 answer:
Natalka [10]3 years ago
8 0

Answer:

⁶¹₂₉Cu + ⁴₂He --->⁶⁵₃₁Ga

Explanation:

Nuclear reactions are reactions which occur with changes in the nucleus of an atom. Nuclear reactions usually occur with the release of large amounts of energy and radiation. Radiactive elements are elements that are involved in nuclearbreactions due to the unstable nature of their nucleus. They disintegrate spontaneously with the emission of radiations. The major types of radiations released during nuclear reactions are;

1, Alpha particles - these are positively charged radiations with strong ionizing power. Each alpha particle is a helium nucleus

2. Beta particles - these are very fast moving stream of electrons. They are negatively charged particles .

3. Gamma radiation - is a form of electromagnetic radiation.

In the alpha absorption of Cu-61, the proton number of the atom increases by 2 while the mass number increases by 4 and the Cu-61 atom is changed to Ga-65 atom. The nuclear equation is given as follows:

⁶¹₂₉Cu + ⁴₂He --->⁶⁵₃₁Ga

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Answer:

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3 years ago
What is factor that is covered up by another trait Dominant or recessive
Veseljchak [2.6K]

Answer: Recessive

Explanation: The recessive trait is often faded away by the dominant/other

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3 years ago
Fe3O4(s) + 4H2(g)3Fe(s) + 4H2O(g) Using standard thermodynamic data at 298K, calculate the entropy change for the surroundings w
alexandr402 [8]

Answer:

dS= 1.79*169.504

j/k = 303.41 j/k

Explanation:

Fe3O4(s) + 4H2(g) --> 3Fe (s)+ 4H2O(g)

dS(Fe3O4) =146.4 j/k

dS(H2) =130.684

dS(Fe) =27.78

dS(H2O) =188.825

dSrxn = dS[product]-dS[reactants]

= 3*dS(Fe)+ 4*dS(H2O)-[1*dS(Fe3O4)+ 4dS(H2)]

= [3*27.78 +4*188.825-146.4 -4*130.684] j/k = 169.504 j/k

This is the dS for 1mole Fe3O4

for 1.79 mols Fe3O4

dS= 1.79*169.504 j/k = 303.41 j/k

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3 years ago
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