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noname [10]
3 years ago
12

61 Cu 29 Write the complete nuclear equations for alpha absorption

Chemistry
1 answer:
Natalka [10]3 years ago
8 0

Answer:

⁶¹₂₉Cu + ⁴₂He --->⁶⁵₃₁Ga

Explanation:

Nuclear reactions are reactions which occur with changes in the nucleus of an atom. Nuclear reactions usually occur with the release of large amounts of energy and radiation. Radiactive elements are elements that are involved in nuclearbreactions due to the unstable nature of their nucleus. They disintegrate spontaneously with the emission of radiations. The major types of radiations released during nuclear reactions are;

1, Alpha particles - these are positively charged radiations with strong ionizing power. Each alpha particle is a helium nucleus

2. Beta particles - these are very fast moving stream of electrons. They are negatively charged particles .

3. Gamma radiation - is a form of electromagnetic radiation.

In the alpha absorption of Cu-61, the proton number of the atom increases by 2 while the mass number increases by 4 and the Cu-61 atom is changed to Ga-65 atom. The nuclear equation is given as follows:

⁶¹₂₉Cu + ⁴₂He --->⁶⁵₃₁Ga

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The two main classes of mixtures are
Vesnalui [34]
Homogeneous or heterogeneous, Hope this helps!!
3 0
3 years ago
Read 2 more answers
Neptunium-237 undergoes a series of α-particle and β-particle productions to end up as thallium-205. How many α particles and β
Fantom [35]
<h3>Answer:</h3>

8 alpha particles

4 beta particles

<h3>Explanation:</h3>

<u>We are given;</u>

  • Neptunium-237
  • Thallium-205
  • Neptunium-237 undergoes beta and alpha decay to form Thallium-205.

We are required to determine the number of beta and alpha particles produced to complete the decay series.

  • We need to know that when a radioisotope emits an alpha particle the mass number reduces by 4 while the atomic number decreases by 2.
  • When a beta particle is emitted the mass number of the radioisotope increases by 1 while the atomic number remains the same.

In this case;

Neptunium-237 has an atomic number 93, while,

Thallium-205 has an atomic number 81.

Therefore;

²³⁷₉₃Np → x⁴₂He + y⁰₋₁e + ²⁰⁵₈₁Ti

We can get x and y

237 = 4x + y(0) + 205

237-205 = 4x

4x = 32

 x = 8

On the other hand;

93 = 2x + (-y) + 81

but x = 8

93 = 16 -y + 81

y = 4

Therefore, the complete decay equation is;

²³⁷₉₃Np → 8⁴₂He + 4⁰₋₁e + ²⁰⁵₈₁Ti

Thus, Neptunium-237 emits 8 alpha particles and 4 beta particles to become Thallium-205.

5 0
2 years ago
What is the percent yield of CuS for the following reaction given that you start with 15.5 g of Na2S and 12.1 g CuSO4? The actua
notka56 [123]

Answer:

(B) 42.1%

Explanation:

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Given: For Na_2S

Given mass = 15.5 g

Molar mass of Na_2S = 78.0452 g/mol

<u>Moles of Na_2S = 15.5 g / 78.0452 g/mol = 0.1986 moles</u>

Given: For CuSO_4

Given mass = 12.1 g

Molar mass of CuSO_4 = 159.609 g/mol

<u>Moles of CuSO_4 = 12.1 g / 159.609 g/mol = 0.0758 moles</u>

According to the given reaction:

Na_2S+CuSO_4\rightarrow Na_2SO_4+CuS

1 mole of Na_2S react with 1 mole of CuSO_4

0.1986 mole of Na_2S react with 0.1986 mole of CuSO_4

Available moles of CuSO_4 = 0.0758 moles

Limiting reagent is the one which is present in small amount. Thus, CuSO_4 is limiting reagent. (0.0758 < 0.1986)

The formation of the product is governed by the limiting reagent. So,

1 mole of CuSO_4 gives 1 mole of CuS

0.0758 mole of CuSO_4 gives 0.0758 mole of CuS

Molar mass of CuS = 95.611 g/mol

Mass of CuS = Moles × Molar mass = 0.0758 × 95.611 g = 7.2473 g

Theoretical yield = 7.2473 g

Given experimental yield = 3.05 g

% yield = (Experimental yield / Theoretical yield) × 100 = (3.05/7.2473) × 100 = 42.1 %

<u>Option B is correct.</u>

6 0
3 years ago
When assigning quantum numbers, how many of the same quantum values may two electrons in the same atom share?
olga55 [171]
Three that is the answer to your question
5 0
3 years ago
How many molecules of ethanol (c2h5oh) (the alcohol in alcoholic beverages) are present in 155 ml of ethanol? the density of eth
ozzi

First convert volume to mass:

mass = 0.789 g/mL * 155 mL = 122.295 g

 

Then convert mass to number of moles:

number of moles = 122.295 g * (1 mole / 46 g) = 2.66 moles

 

Using avogadros number, we get the molecules:

<span>number of molecules = 2.66 moles * 6.022 x 10^23 molecules / mole = 1.6 x 10^24 molecules</span>

4 0
2 years ago
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