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Sergio039 [100]
3 years ago
8

____ is involved in glucose metabolism.

Chemistry
1 answer:
krek1111 [17]3 years ago
7 0

I took the test and the answer is chronium

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Calculate the molar concentration of the Cl⁻ ions in 0.65 M CaCl2(aq), assuming that the dissolved substance dissociates complet
alexandr1967 [171]
The question here is solved using basic chemistry. CaCl2(aq) is an ionic compound which will have the releasing of 2 Cl⁻ ions ions in water for every molecule of CaCl2 that dissolves.
CaCl2(s) --> Ca+(aq) + 2 Cl⁻(aq)
            [Cl⁻] = 0.65 mol CaCl2/1L × 2 mol Cl⁻ / 1 mol CaCl2 = 1.3 M
The answer to this question is [Cl⁻] = 1.3 M
5 0
3 years ago
What evidence supports Bohr’s claim that an electron is found only in specific energy levels around the nucleus of the atom. And
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Energy Levels of Electrons. As you may remember from chemistry, an atom consists of electrons orbiting around a nucleus. ... They are restricted to orbits with only certain energies. Electrons can jump from one energy level to another, but they can never have orbits with energies other than the allowed energy levels.

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What is the measure of the amount of water in the air
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The amount of water in the air is humidity .
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3 years ago
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If the hydroxide ion [OH-] concentration of an aqueous solution is 1 x 10 -3 M, what is the [H+] in the solution? Is the solutio
Dominik [7]

Answer:

pH = 11, The solution is Basic.

Explanation:

We know that;

[OH-] [H+] = 1 × 10^-14

we are given; [OH-] as 1 x 10^ -3 M

Therefore, we can get the [H+] by;

[H+] = 1 × 10^-14/[OH-]

       = 1 × 10^-14 M/1 x 10^ -3 M

       =  1 × 10^-11 M

But; pH = - log [H+]

Thus,

pH = - log (1 ×10^-11 M)

     =  11

pH = 11, which means the solution is basic.

4 0
3 years ago
15. A 15.30 g sample of calcium (Ca) combines with 7.96 g of sulfur(S) to form calcium sulfide
BlackZzzverrR [31]

Answer:

17.689g

Explanation:

1: First, write out the equation you will follow:

Ca + S ⇒ CaS

2: Use the formula Mass = Mr x moles to work out the moles of both Ca and S - this will enable you to find the limiting reactant.

3: Moles Ca:

Moles = mass/ Mr = 15.3/ 40.1 = 0.382 moles.

4: Moles S:

Moles = mass/ Mr = 7.96/ 32.1 = 0.245 moles.

5: We now know S is the limiting reactant, and as there is a 1:1 ratio between S and CaS, there will also be 0.245 moles CaS.

6: Mass CaS:

Mass = Mr x moles = 72.2 x 0.245 = 17.689g

6 0
3 years ago
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