Not sure about these either...

What is the greatest common factor in the distributive property to find each sum of 30+66

Verizon [17]

6 is the greatest common factor of 30 and 66, because 6(5+11)

3 0

3 years ago

Hit me up if ur bored but what's 7x-2y=23 squared

goblinko [34]

Simplify 7x + 2y = -23 Solving 7x + 2y = -23 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-2y' to each side of the equation. 7x + 2y + -2y = -23 + -2y Combine like terms: 2y + -2y = 0 7x + 0 = -23 + -2y 7x = -23 + -2y Divide each side by '7'. x = -3.285714286 + -0.2857142857y Simplifying x = -3.285714286 + -0.2857142857y

5 0

2 years ago

You believe the population is normally distributed. Find the 80% confidence interval. Enter your answer as an open-interval (i.e

victus00 [196]

You intend to estimate a population mean μ from the following sample. 26.2 27.7 8.6 3.8 11.6 You believe the population is normally distributed. Find the 80% confidence interval. Enter your answer as an open-interval (i.e., parentheses) accurate to twp decimal places.

Answer:

The Confidence interval = (8.98 , 22.18)

Step-by-step explanation:

From the given information:

mean = $\dfrac{ 26.2+ 27.7+ 8.6+ 3.8 +11.6 }{5}$

mean = 15.58

the standard deviation $\sigma$ = $\sqrt{\dfrac{\sum(x_i - \mu)^2 }{n}}$

the standard deviation = $\sqrt{\dfrac{(26.2 - 15.58)^2 +(27.7 - 15.58)^2 +(8.6 - 15.58)^2 + (3.8 - 15.58)^2 + (11.6 - 15.58)^2 }{5 } }$

standard deviation = 9.62297

Degrees of freedom df = n-1

Degrees of freedom df = 5 - 1

Degrees of freedom df = 4

For df at 4 and 80% confidence level, the critical value t from t table = 1.533

The Margin of Error M.O.E = $t \times \dfrac{\sigma}{\sqrt{n}}$

The Margin of Error M.O.E = $1.533 \times \dfrac{9.62297}{\sqrt{5}}$

The Margin of Error M.O.E = $1.533 \times 4.3035$

The Margin of Error M.O.E = 6.60

The Confidence interval = ( $\mu \pm M.O.E$ )

The Confidence interval = ( $\mu + M.O.E$ , $\mu - M.O.E$ )

The Confidence interval = ( 15.58 - 6.60 , 15.58 + 6.60)

The Confidence interval = (8.98 , 22.18)

7 0

2 years ago

What is the expression of one less than the quotient of four and a number x

Maru [420]

The expression is: (4/x) -1

7 0

3 years ago

Read 2 more answers

Mohit pays rupees 9000 as an amount on the sum of rupees 7000 that he had borrowed for 2 years.

Sphinxa [80]

Answer:

The required rate of interest = 14.285%

Step-by-step explanation:

Here, The principal amount = 7,000

The final paid amount = 9,000

Time = 2 years

Let us assume the rate of interest = R

Now, Simple Interest = Amount - Principal

= 9,000 - 7,000 = 2,000

So, the SI on the given principal for 2 years = 2,000

$\textrm{SIMPLE INTEREST } = \frac{P \times R \times T}{100}\\\implies 2000 = \frac{7,000 \times R \times 2}{100}\\\implies R = \frac{2,000 \times 100}{7,000 \times 2} = 14.285$

or, R = 14.285%

Hence, the required rate of interest = 14.285%

8 0

3 years ago