Answer:
I think that it is mate selection though not sure
Answer: the answer is
7.92 hrs
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Explanation:
B: A mutation in one of G5W's parents, during gamete formation, created an X-linked dominant disease allele.
You need to analyze the sex gametes.
Boys are XY
Girls are XX
If you have an X-linked dominant disease you need only one affected X gamete to have the disease.
The mother has XX' where X' is de affected and reproduce with a healthy man XY and breed unhealthy boys, but because of the heterozygous gametes you could also have healthy ones XX and XY
1: There are four stages of meiosis including prophase, metaphase, anaphase, and telophase. In the prophase phase (first stage) the chromosomes becomes visible as paired chromatids. When this happens the nuclear envelope disappears. During metaphase (second stage) the chromosomes attach to the spindle fibers. Throughout anaphase (third phase) the chromosomes move to opposite sides of the spindle fibers. While in telophase (fourth stage) two nuclei form by chromosomes and chromatids moving to the opposite ends of the cell.
2: The cells that outcome from meiosis are haploid daughter cells.
3: Haploid.
4: The similarities of meiosis and mitosis are that they both outcome with daughter from a parent cell. Differences are that mitosis has one round of genetic separation and cellular division while meiosis has two. In meiosis it creates daughter cells that aren’t identical.
Sexual reproduction combines genetics from two parents while asexual reproduction have offspring exactly the same as the genetics of the parent.
Asexual reproduction has the advantage of quicker reproducing. Sexual reproduction have all different offspring that can adapt to many different environments.
