If the distance between two charges is halved, the electrical force between them increases by a factor 4.
In fact, the magnitude of the electric force between two charges is given by:
where
k is the Coulomb's constant
q1 and q2 are the two charges
r is the separation between the two charges
We see that the magnitude of the force F is inversely proportional to the square of the distance r. Therefore, if the radius is halved:
the magnitude of the force changes as follows:
so, the force increases by a factor 4.
Answer:
W = 12 kJ
Explanation:
We have,
Voltage of a battery is 12 V
Charge supplied by the battery is 1000 C
It is assumed to find the work is done by the battery in moving the charge. The work done is given in terms of voltage as :
or
W = 12 kJ
So, the work of 12 kJ is done by battery in moving charges.