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2 years ago

Which technology contains at least one permanent magnet?

Physics

2 answers:

stich3 [128]2 years ago

6 0

I’m pretty sure it’s, B. An Electric Motor. I apologize in advance if it’s incorrect.

Xelga [282]2 years ago

4 0

Answer: B

Explanation: took it on ape x I know the other guy said it this is just for reassurance

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Define investigation to show its scientific meaning.

Murrr4er [49]

Answer:

the action of investigating something or someone; formal or systematic examination or research.

Explanation:

This definition is provided by Oxford Languages

7 0

3 years ago

Haley is trying to pull an object upward. The below forces are acting on the object.

ra1l [238]

For this case, the first thing we must do is define a reference system.

Suppose that the positive direction of the reference system is upward.

We have that the sum of forces in the vertical axis is given by:

Fy = Fp - Fg

Substituting values:

Fy = 5500 - 6000

Fy = - 500

The negative sign means that the direction of the force with respect to the defined coordinate system is downward.

Answer:

The net force is:

↓ 500N

3 0

2 years ago

Read 2 more answers

Unele rigle gradate au partea pe care sunt imprimante graditatiile in forma de pana. prezinta aceasta vreo importanta pentru mas

GrogVix [38]

Da ne ajuta pentru a putea citi corect lungimea ... coronită???

7 0

2 years ago

A lighthouse is located on a small island, 3 km away from the nearest point on a straight shoreline, and its light makes four re

lbvjy [14]

Answer:

The beam of light is moving at the peed of:

$\frac{dy}{dt} = \frac{80\pi}{3}$ km/min

Given:

Distance from the isalnd, d = 3 km

No. of revolutions per minute, n = 4

Solution:

Angular velocity, $\omega = \frac{d\theta'}{dt} = 2\pi n = 2\pi \times 4 = 8\pi$ (1)

Now, in the right angle in the given fig.:

$tan\theta' = \frac{y}{3}$

Now, differentiating both the sides w.r.t t:

$\frac{dtan\theta'}{dt} = \frac{dy}{3dt}$

Applying chain rule:

$\frac{dtan\theta'}{d\theta'}.\frac{d\theta'}{dt} = \frac{dy}{3dt}$

$sec^{2}\theta'\frac{d\theta'}{dt} = \frac{dy}{3dt} = (1 + tan^{2}\theta')\frac{d\theta'}{dt}$

Now, using $tan\theta = \frac{1}{m}$ and y = 1 in the above eqn, we get:

$(1 + (\frac{1}{3})^{2})\frac{d\theta'}{dt} = \frac{dy}{3dt}$

Also, using eqn (1),

$8\pi\frac{10}{9})\theta' = \frac{dy}{3dt}$

$\frac{dy}{dt} = \frac{80\pi}{3}$

7 0

2 years ago

A 70.0 kg sprinter starts a race with an acceleration of 1.60 m/s^2, What is the net external force (in N) on him? (Enter the ma

Ierofanga [76]

Answer:

External force on him will be 112 N

Explanation:

We have given the mass of the sprinter m =70 kg

Acceleration of the sprinter $a=1.6m/sec^2$

We have to find the net external force

According to second law of motion force = mass ×acceleration

Force is dependent on the mass and acceleration

So $F=70\times 1.6=112 N$

So external force will be 112 N

6 0

3 years ago