1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Paha777 [63]
3 years ago
5

As an emergency vehicle approaches Bob and moves away from Jill, how does the actual frequency of the siren change? A) As an eme

rgency vehicle approaches Bob the frequency increases. B) As an emergency vehicle moves away from Jill the frequency decreases. C) The actual frequency of the siren does not change despite appearances. D) Bob does not notice any change until the vehicle passes him and the siren increases.
Physics
1 answer:
uysha [10]3 years ago
8 0

Answer:

the answer is actualy C i did it on usatestprep

Explanation:

You might be interested in
What quantities determine the resistance of a piece of material? Choose all that apply.
bija089 [108]

Answer:

Option (a), (b) and (c)

Explanation:

The resistance of a conductor depends on the length of the conductor, area of crossection of the conductor and the nature of the conductor.

The formula for the resistance is given by

R = ρ x l / A

Where, ρ is the resistivity of the conductor, l be the length of the conductor and A be the area of crossection of the conductor.

So, It depends on the length, area and the type of material.

7 0
3 years ago
A spring is 17 cm long when it is lying on a table. One end is then attached to a hook and the other end is pulled by a force th
RideAnS [48]

Answer:

im pretty sure it B but I recommend waiting for another person. I used the workdone formula (Force*Dictance*cos(theta) and got 55 Joules

Explanation:

8 0
3 years ago
Select the correct answer.
andrew-mc [135]
I think the answer would be C
7 0
3 years ago
Read 2 more answers
A train can speed up at a uniform rate of 0.15 m/s2. In what minimum distance can
goblinko [34]

Answer:

d = 2083.33 m

Explanation:

Given that,

Acceleration of the train, a = 0.15 m/s²

The initial speed of the car, u = 0\

Final velocity, v = 25 m/s

We need to find the minimum distance covered by the train. Let it is d. Using third equation of kinematics as follows :

v^2-u^2=2ad\\\\d=\dfrac{v^2-u^2}{2a}\\\\d=\dfrac{(25)^2-0}{2\times 0.15}\\\\d=2083.33\ m

So, the minimum distance is 2083.33 m

3 0
3 years ago
Please I really need help on this please help thank you
maw [93]
What do you need help with?
4 0
3 years ago
Other questions:
  • to remove a tight-fitting jar, megan runs the lid under hot water. What happends to the jar lid when its temperature increases?
    14·1 answer
  • To pull an old stump out of the ground, you and a friend tie two ropes to the stump. You pull on it with a force of 500 N to the
    7·1 answer
  • Light from the sun heats Earth's atmosphere. When the air becomes warmer, it expands. Which type of energy increases to cause th
    15·2 answers
  • A rock climber is going up a narrow space between two vertical rocks. The distance between the rocks allows the climber to brace
    15·1 answer
  • An alternative to CFL bulbs and incandescent bulbs are light-emitting diode (LED) bulbs. A 16-W LED bulb can replace a 100-W inc
    7·1 answer
  • Write a paragraph of no less than five sentences explaining how Newton's First Law of Motion supports people's need to wear seat
    12·1 answer
  • What is the mass of a bicycle that has 90 kg.m/s of momentum at a speed of 6 m/s?
    6·1 answer
  • two porters are available to carry a long timber wood.out of them one is weak.how to do you make less load to the weak one? writ
    10·1 answer
  • Your friend phred says ""i decided to make one of those online personality tests as a project in my psychology class. how hard c
    12·1 answer
  • two charges experience exert a force of 1n on each other when they are 1m apart. what force will these charges experience if the
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!