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riadik2000 [5.3K]
3 years ago
5

Why is there no effect on other branches in a paral- lel circuit when one branch of the circuit is opened or closed?

Physics
1 answer:
motikmotik3 years ago
6 0

Answer:

Explanation:

As the circuit is parallel, then there is no effect of other branches as the potential difference across each arm is same.

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The H line in Calcium is normally at 396.9nm. however, in a star’s spectrum it is measured at 398,1 nm. How fast is the star mov
konstantin123 [22]

H line of Calcium spectrum is normally given as 396.9 nm

Now from a distant star we measured it as 398.1 nm

So here this change in the wavelength of distant star is due to Doppler's effect of light as per which when source of light moves towards the observer then the frequency of light received will appear different from its actual frequency

So here we can say as per Doppler's effect of light

\frac{\Delta \nu}{\nu_0} = \frac{v}{c}

\frac{\nu' - \nu}{\nu_0} = \frac{v}{c}

\frac{\frac{1}{\lambda} - \frac{1}{\lambda'}}{\frac{1}{\lambda}} = \frac{v}{c}

\frac{\lambda' - \lambda}{\lambda'} = \frac{v}{c}

given that

\lambda' = 398.1 nm

\lambda = 396.9 nm

c = 3 * 10^8 m/s

\frac{398.1 - 396.9}{398.1} = \frac{v}{3*10^8}

v = 3*10^8 * \frac{1.2}{398.1}

v = 9.04 * 10^5 m/s

so the start is moving away with speed 9.04 * 10^5 m/s because when wavelength is more than the real wavelength then its frequency is less which mean it is moving away from the Earth

5 0
3 years ago
A paper weight is dropped from the roof of a block of multi story flats. Each storey being 3 metre high. It passes the ceiling o
docker41 [41]
Use equations of motion to get the correct answer!
6 0
3 years ago
Why is it so difficult for astronomers to see new stars in the process of birth?
vekshin1
Birth happens very quickly, so it is hard to "catch" stars in the act. - most stars are born inside dusty clouds, which block any light that may be coming from the stars.
4 0
1 year ago
Which of the following is equal to 1W?<br><br>A.1 J<br>B.1 J/s<br>C.1 J·s<br>D.1 N·m
Ray Of Light [21]
B. Extra text to get to 20 characters.
7 0
2 years ago
Two equipotential surfaces surround a +3.10 x 10-8-c point charge. how far is the 290-v surface from the 41.0-v surface?
MrMuchimi
 T<span>he equation to be used here to determine the distance between two equipotential points is:
V = k * Q / r 

where v is the voltage of the point, k is a constant, Q is charge of the point measured in coloumbs and r is the distance. 
In this case, we can use ratio of proportions to determine the distance between the two points. in this respect, 

Point 1: 
V = k * Q / r = 290
r = k*Q/290 ; kQ = 290r

Point 2:
V = k * Q / R = 41
R = k*Q/41
from equation 10 kQ = 290r
R = 290/(41)= 7.07 m 
The distance between the two points then is equal to 7.07 m.


</span>
8 0
2 years ago
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