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riadik2000 [5.3K]
3 years ago
5

Why is there no effect on other branches in a paral- lel circuit when one branch of the circuit is opened or closed?

Physics
1 answer:
motikmotik3 years ago
6 0

Answer:

Explanation:

As the circuit is parallel, then there is no effect of other branches as the potential difference across each arm is same.

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solids, liquids, and gases are three forms of matter that:a. take up space. b. have mass. c. are made of atoms. d. all of the ab
LiRa [457]

Answer:

d

Explanation:

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3 years ago
What is a literature review?<br>​
almond37 [142]

Answer: A literature review consists of an overview, a summary, and an evaluation (“critique”) of the current state of knowledge about a specific area of research.

Explanation:

7 0
2 years ago
Name three different avenues by which Thomas Edison received an education
klio [65]
Edison's education is most unique and relevant.

1. The first teacher he had was his mother
2. He found vital lessons and was influenced greatly by the book of R.G. Parker called School of Natural Philosophy
3. Another educating piece he had was a book entitled The Cooper Union for the Advancement of Science and Art

His style of learning was though reading books on a variety of subjects, a self-educating environment that fosters independent learning which can be useful through his life.
5 0
3 years ago
A hot rod can accelerate from 0 to 60 km/h in 5.4 s.
mylen [45]

Answer:

<h2>a) Acceleration is 3.09 m/s²</h2><h2>b) Distance traveled is 45.05 m</h2><h2>c) Time taken to travel 250 m is 12.72 s</h2>

Explanation:

a) We have equation of motion v = u + at

      Initial velocity, u = 0 km/hr = 0 m/s

      Final velocity, v = 60 km/hr = 16.67 m/s  

      Time, t = 5.4 s

      Substituting

                       v = u + at  

                       16.67 = 0 + a x 5.4

                       a = 3.09 m/s²

      Acceleration is 3.09 m/s²

b) We have equation of motion s = ut + 0.5 at²

         Initial velocity, u = 0 m/s

         Acceleration, a = 3.09 m/s²

         Time, t = 5.4 s      

      Substituting

                       s = ut + 0.5 at²

                       s = 0 x 5.4 + 0.5 x 3.09 x 5.4²

                       s = 45.05 m

       Distance traveled is 45.05 m

c) We have equation of motion s = ut + 0.5 at²

         Initial velocity, u = 0 m/s

         Acceleration, a = 3.09 m/s²

         Displacement, s = 0.25 km = 250 m      

      Substituting

                       s = ut + 0.5 at²

                       250 = 0 x t + 0.5 x 3.09 xt²

                       t = 12.72 s

       Time taken to travel 250 m is 12.72 s

6 0
2 years ago
2.2 x 10^-5 um = _______ km
drek231 [11]
The answer is 2.2 × 10^-14<span> kilometers

hope this helps</span>
3 0
3 years ago
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