What is one of the forms of a gene called?

A sample of gas has a volume of 25L at a pressure of 200 kPa and a temperature of 25°C. What would be the volume if the pressure

frozen [14]

Answer:

18 L

Explanation:

Use ideal gas law:

PV = nRT

Find initial number of moles, but first convert to units that match the gas constant units.

(200,000 Pa) (0.025 m³) = n (8.314 Pa m³ / mol / K) (25 + 273.15 K)

n = 2.017 mol

At the new pressure and temperature:

(250,000 Pa) V = (2.017 mol) (8.314 Pa m³ / mol / K) (0 + 273.15 K)

V = 0.018 m³

V = 18 L

3 0

4 years ago

An astronaut drops a hammer from 2.0 meters above the surface of the Moon. If the acceleration due to gravity on the Moon is 1.6

Elenna [48]

Answer:

option C

Explanation:

given,

height of the hammer, h = 2 m

acceleration due to gravity of the moon, g = 1.62 m/s²

time taken by the hammer to reach at bottom = ?

initial speed of the hammer, u = 0 m/s

using equation of motion for the time calculation

$s = ut + \dfrac{1}{2}gt^2$

$2 = 0+\dfrac{1}{2}\times 1.62\times t^2$

t² = 2.469

t = 1.57 s ≅ 1.6 s

hence, the time taken by the hammer to reach the bottom is equal to 1.6 s.

The correct answer is option C

8 0

4 years ago

A cell phone company relies on which kind of waves in order to provide service for its customers? ultraviolet waves infrared wav

Greeley [361]

Answer:

microwaves

Explanation:

Electromagnetic waves consist of waves of different wavelengths. Among the choices given, waves are ordered for increasing wavelengths as follows:

gamma rays --> ultraviolet waves --> infrared waves --> microwaves

So, microwaves are the waves with the longer wavelength among the given choices. This is the reason why they are used by the cell phone companies: in fact, since they have longer wavelengths, microwaves can travel longer distances without being absorbed by objects or obstacles, and so they are more reliable for broadcasting and telecommunications.

6 0

3 years ago

Read 2 more answers

A balloon is filled with a gas at 111 kPa when the temperature was 22*C. If the temperature

storchak [24]

119.7kPa

Explanation:

Given parameters:

Pressure of gas in balloon = 111kPa

Temperature of gas = 22°C

Final temperature = 45°C

Unknown:

Final pressure = ?

Solution:

Since the gases in the balloon have the same number of moles. We can apply a derivative of the combined gas law to solve this problem.

At constant volume the pressure of a given mass of gas varies directly with the absolute temperature.

$\frac{P1}{T1} = \frac{P2}{T2}$

P1 is the initial pressure

P2 is the final pressure

T1 is the initial temperature

T2 is the final temperature

convert from celcius to kelvin:

tK = 273 + tC

T1 = 273 + 22 = 295K

T2 = 273 + 45 = 318K

$\frac{111}{295} = \frac{P2}{318}$

P2 = 119.7kPa

learn more:

Ideal gas brainly.com/question/13064292

#learnwithBrainly

3 0

3 years ago

Two rockets are flying in the same direction and are side by side at the instant their retrorockets fire. Rocket A has an initia

earnstyle [38]

Answer:

The acceleration of rocket B is -22.24 m/s²

Explanation:

Two rockets are flying in the same direction and are side by side at the

instant their retrorockets fire

That means they started from the same point at the same time

Rocket A has an initial velocity of 5800 m/s

Rocket B has an initial velocity of 8600 m/s

After a time t both rockets are again side by side, the displacement of

each being zero

That means they are in the same position again → s = 0

The acceleration of rocket A is -15 m/s²

We need to find the acceleration for rocket B

We can find the time from the information of rocket A by using the

rule → s = u t + $\frac{1}{2}$ a t²

where s is the displacement, u is the initial velocity, a is the

acceleration, and t is the time

→ s = 0 , u = 5800 m/s , a = -15 m/s²

Substitute these values in the rule

→ 0 = 5800 t + $\frac{1}{2}$ (-15) t²

→ 0 = 5800 t - 7.5 t²

Add 7.5 t² for both sides

→ 7.5 t² = 5800 t

Divide both sides by 7.5 t

→ t = 773.3 s

The time for the both rocket to have displacement zero is 773.3 s

Now we can find the acceleration of the rocket B by using the same

rule above

→ u = 8600 m/s , t = 773.3 , s = 0

→ 0 = (8600)(773.3) + $\frac{1}{2}$ a (773.3)²

→ 0 = 6650380 + 298996.445 a

Subtract 6650380 from both sides

→ -6650380 = 298996.445 a

Divide both sides by 298996.445

→ a = -22.24 m/s²

<em>The acceleration of rocket B is -22.24 m/s²</em>

6 0

4 years ago