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loris [4]
3 years ago
7

Pls help me asap!!!!

Mathematics
1 answer:
RUDIKE [14]3 years ago
5 0

Answer:b

Step-by-step explanation:y=2x-3

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Maggie bought 3 dozen muffins from a baker for $48. Find the costs of 1 dozen muffins and 9 dozen muffins.
Gennadij [26K]
We will say that d = 1 dozen. and y = cost

we know that 3 dozen is 48. so
3d = 48.

to get the cost of 1d, we have to get the 3 to change into a 1. the only way to do this is to divide 3 by 3. if we divided the left side by 3 we must also do the right so:
3d = 48
1d = 16

so 1 dozen = 16

to change 3d into 9d we have to multiply by 3. we again have to do this to both sides. so:
3d = 48
9d = 144
7 0
3 years ago
If 25 is subtracted from the square of a positive integer, the result is 200. Find the positive
yulyashka [42]

Answer:

150

Step-by-step explanation:

5 0
3 years ago
Find the zeros of the following<br> please solve step by step<br> 1. x³+9x²+26x+24=0
Vlad1618 [11]

Answer: -4, -3, -2

Step-by-step explanation:

By inspection, we know x=-2 is a root.

We can thus rewrite the equation as

(x+2)\left(\frac{x^3 + 9x^2 + 26x+24}{x+2} \right)=0\\\\(x+2)(x^2 + 7x+12)=0\\\\(x+2)(x+3)(x+4)=0\\\\x=-4, -3, -2

3 0
2 years ago
What are the x intercepts for the graph of y= 3 ( x +1 )(x-6)
leonid [27]
The x intercepts occur when you set the factors equal to 0. x+1=0 & x-6=0 gives you the x-intercepts. x+1=0 -> x=-1. x-6=0 -> x=6. Therefore, -1 & 6 are your x intercepts
3 0
3 years ago
Given the function g(x) = 4(3)x, Section A is from x = 1 to x = 2 and Section B is from x = 3 to x = 4.
Rudik [331]
The question is defective, or at least is trying to lead you down the primrose path.
The function is linear, so the rate of change is the same no matter what interval (section) of it you're looking at.
The "rate of change" is just the slope of the function in the section.  That's
         (change in f(x) ) / (change in 'x') between the ends of the section.
In Section A:Length of the section = (1 - 0) = 1f(1) = 5f(0) = 0change in the value of the function = (5 - 0) = 5Rate of change =            (change in the value of the function) / (size of the section) = 5/1  =  5
In Section B:Length of the section = (3 - 2) = 1 f(3) = 15f(2) = 10change in the value of the function = (15 - 10) = 5Rate of change =           (change in the value of the function) / (size of the section) = 5/1  =  5
Part A:The average rate of change of each section is 5.
Part B:The average rate of change of Section B is equal to the average rate of change of Section A.
Explanation:The average rates of change in every section are equalbecause the function is linear, its graph is a straight line,and the rate of change is just the slope of the graph.

4 0
3 years ago
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