Answer:
55.3 N, 223.3 N
Explanation:
First of all, we can find the angle of the inclined plane.
We have:
L = 5 m the length of the incline
h = 1.2 m is the height
We also have the relationship

where
is the angle of the incline. Solving for the angle,

Now we can find the components of the weight of the box, which is the force that the box exerts on the plank. Calling W = 230 N the weight of the box, we have:
- Component parallel to the incline:

- Component perpendicular to the incline:

As the climber climbs the mountain, he needs to over his or her own weight component along the slope of the mountains.
By Newton's second law: Net force = Mass x acceleration
Hence, greater the mass, greater will be the force required to move up the mountain. Hence, the climber will need to apply higher force to climb up as he or she has packed too much, which resulted in the increase in the mass. Hence, there is a increase in the force which will pull him or her downward.
Answer:
The answer is a2 = 4.48 m/s2
Explanation:
Let´s start with the equations we know:


Where:
=> Final velocity
=> Initial velocity- a => acceleration
- t => time
Now, let´s divide the problem in Stage 1 and 2 and get equations for each stage:
Stage 1 knowns and unknowns:
Stage 1 equation:
Stage 2 knowns and unknowns:
Stage 2 equation:
Now we can substitute the resultant equation from stage 1 into stage´s 2 equation:
We can see "t" is on both sides, so it cancels out and we are left with:
![a_{2} = 4.48 [\frac{m}{s^{2} } ]](https://tex.z-dn.net/?f=a_%7B2%7D%20%3D%204.48%20%5B%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%20%7D%20%5D)
Answer
given,
initial velocity of the ball, u = 40 m/s
final velocity of the ball, v= -40 m/s
time of contact = 0.013 s
mass of the ball = 0.059 Kg
a) initial momentum
P₁ = m u = 0.059 x 40 = 2.36 kg.m/s
final momentum
P₂ = m v = 0.059 x (-40) = -2.36 kg.m/s
b) change in momentum
Δ P = P₂- P₁
Δ P = -2.36 - 2.36
Δ P = -4.72 kg.m/s
c) Average force
average force exerted by the ball is equal to change in momentum per unit time.


F = -363 N
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