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Evgen [1.6K]
3 years ago
7

Write a short note on Andromeda galaxy.​

Physics
2 answers:
AveGali [126]3 years ago
5 0

Answer:

\sf\pink{Andromeda \: galaxy}

The Andromeda is a galaxy which is nearest to the milky way. It is also named as Messier 31 or M31 or NGC 224. It is a spiral galaxy located at a distance of approximately 2.5 million light years from earth.

another name Andromeda in Hindi is Vaikunth.

erik [133]3 years ago
5 0

Explanation:

The Andromeda Galaxy (IPA: /ænˈdrɒmɪdə/), also known as Messier 31, M31, or NGC 224 and originally the Andromeda Nebula (see below), is a barred spiral galaxy approximately 2.5 million light-years (770 kiloparsecs) from Earth and the nearest major galaxy to the Milky Way.

Number of stars: ~1 trillion (1012)

Right ascension: 00h 42m 44.3s

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An aluminum wire with a diameter of 0.115 mm has a uniform electric field of 0.235 V/m imposed along its entire length. The temp
tekilochka [14]

Answer with Explanation:

We are given that

Diameter of coil=d=0.115mm

Radius, r=\frac{d}{2}=\frac{0.115}{2}=0.0575mm=0.0575\times 10^{-3} m

Using 1mm=10^{-3} m

Electric field=E=0.235V/m

T=55 degree C

T_0=20^{\circ} C

\rho_0=2.82\times 10^{-8}\Omega m

\alpha=3.9\times 10^{-3}/C

(a).We know that

\rho=\rho_0(1+\alpha(T-T_0))

Substitute the values

\rho=2.82\times 10^{-8}(1+3.9\times 10^{-3}(55-20))

\rho=3.2\times 10^{-8}\Omega m

(b).Current density,J=\frac{E}{\rho}

Using the formula

J=\frac{0.235}{3.2\times 10^{-8}}=7.3\times 10^6A/m^2

c.Total current,I=JA

Where A=\pi r^2

\pi=3.14

Using the formula

I=7.3\times 10^6\times 3.14\times (0.0575\times 10^{-3})^2

I=0.076A

d.Length of wire=l=2m

V=El

Substitute the values

V=0.235\times 2=0.47 V

5 0
3 years ago
A water pipe is inclined 40.0° below the horizontal. The radius of the pipe at the upper end is 2.00 cm. If the gauge pressure a
aliya0001 [1]

Answer:

P_2 = -1.9 \times 10^8 Pa

Explanation:

As it is given that flow rate in the pipe is 20 cm^3/s

so we have

Q = A_1v_1 = A_2v_2

at the upper end the area is given as

A_1 = \pi r_1^2

A_1 = \pi(0.02)^2 = 1.26 \times 10^{-3} cm^2

Also at the other end

A_2 = \pi r_2^2

A_2 = \pi(0.01)^2 = 0.314 \times 10^{-3} cm^2

now the speed at two ends is given as

v_1 = \frac{20}{1.26 \times 10^{-3}}

v_1 = 159.15 m/s

v_2 = \frac{20}{0.314 \times 10^{-3}}

v_2 = 637 m/s

now by Bernoulli's theorem we have

P_1 + \frac{1}{2}\rho v_1^2 + \rho g h_1 = P_2 + \frac{1}{2}\rho v_2^2 + \rho g h_2

now we have

0.112(1.013 \times 10^5) + \frac{1}{2}1000(159.15)^2 + 1000(9.81)(2.65sin40) = P_2 + \frac{1}{2}(1000)(637)^2 + 0

Now we have

P_2 = -1.9 \times 10^8 Pa

4 0
3 years ago
1. What does the word "periodic” mean?
Feliz [49]

Answer:

periodic means appearing or occurring at intervals.

Explanation:

6 0
4 years ago
Read 2 more answers
A machine does 500 j of work in 20 sec. What is the power of this machine?
NNADVOKAT [17]

Explanation:

P=W/t

P=500/20

P=25 W

6 0
3 years ago
What is the most important safety rule in science? A. Never work with chemicals. B. Always use unbreakable glassware. C. Always
sasho [114]
Well based on the three I would think it's C
4 0
3 years ago
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