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solmaris [256]
3 years ago
11

The finished product or waste that forms as a result of a process is known as _______.

Physics
2 answers:
Pie3 years ago
7 0
The finished product or waste that forms as a result of a process is known as by-product.
Trava [24]3 years ago
4 0

The finished product or waste that forms as a result of a process is known as output.

The process of waste management is referred to as waste disposal, where a  sizable proportion of this waste is composed by industrial and dangerous waste. Dangerous and non-dangerous industrial waste should also be very careful managed.

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Water can dissolve almost anything in the universe
Elodia [21]

Answer:

No, its not possible for water to dissolve almost anything in the universe.

Explanation:

Solubility of a solute defines the ability of that solute to dissolve in a given solvent. It is defined as the maximum amount of solute dissolved in a solvent at equilibrium. The solution which results from dissolving this maximum amount is called a saturated solution, and one it has been reached, no more solute can be dissolved in it.

Different substances in the universe have diffferent solubilities in water, some very high (soluble) (eg. sugar and salt) and some very low (insoluble) (eg plastics). The substances that are able to form bonds with water (Hydrogen or Ionic) are more soluble than those who are not able to do so.

5 0
3 years ago
Unpolarized light with intensity I0I0I_0 is incident on an ideal polarizing filter. The emerging light strikes a second ideal po
zvonat [6]

Answer:

0.293I_0

Explanation:

When the unpolarized light passes through the first polarizer, only the component of the light parallel to the axis of the polarizer passes through.

Therefore, after the first polarizer, the intensity of light passing through it is halved, so the intensity after the first polarizer is:

I_1=\frac{I_0}{2}

Then, the light passes through the second polarizer. In this case, the intensity of the light passing through the 2nd polarizer is given by Malus' law:

I_2=I_1 cos^2 \theta

where

\theta is the angle between the axes of the two polarizer

Here we have

\theta=40^{\circ}

So the intensity after the 2nd polarizer is

I_2=I_1 (cos 40^{\circ})^2=0.587I_1

And substituting the expression for I1, we find:

I_2=0.587 (\frac{I_0}{2})=0.293I_0

5 0
2 years ago
What is the sentence that we use to<br> remember how to convert metric<br> prefixes?
Marrrta [24]

Answer:

The mnemonic I can use to memorize the metric prefixes in this order is: Gigantic Monsters Killed One Million Men Napping Peacefully. All right, so again, gigantic monsters killed one million men napping peacefully.

8 0
3 years ago
A long, straight, vertical wire carries a current upward. due east of this wire, in what direction does the magnetic field point
Solnce55 [7]
(I assume that the 4 directions north-south-east-west are meant with respect to the wire seen from the top.)

We can use the right-hand rule to understand the direction of the magnetic field generated by the wire. The thumb follows the direction of the current in the wire (upward), while  the other fingers give the direction of the field in every point around the wire. Seen from the top, the field has an anti-clockwise direction. Therefore, if we take a point at east with respect to the wire, in this point the field has direction south.
8 0
3 years ago
1.2
Alika [10]

Answer:

B

Explanation:

Because it has to increase

3 0
2 years ago
Read 2 more answers
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