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egoroff_w [7]
3 years ago
11

Two masses (5.3kg and 7.5kg) are fastened together with a small amount of explosive. They are loaded into a spring gun that is t

ilted 60.0 ◦ above the horizontal and launched at a speed of 25m/s. At the top of the trajectory, the explosive detonates (assume the mass of explosive is negligble). After it detonates, the 5.3kg mass isn’t moving at all. What is the velocity of the second mass just after the explosion?
Physics
1 answer:
Vsevolod [243]3 years ago
8 0

Answer:

8.2

Explanation:

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the inertial mass of an object is measured by exerting a force on the object and measuring the object's BLANK using an inertial
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14. Convert 22 degrees celsius to fahrenheit.<br> Please show your work
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(22°C × 9/5) + 32 = 71.6°F
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What are the risk of obesity in middle adulthood
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3 years ago
Which interactions are part of the greenhouse effect? Select three options.
Allisa [31]

<u>Out of the given options, the following interactions are part of the greenhouse effect, </u>

  • Gases in the atmosphere absorb heat
  • Earth’s surface radiates energy back into the atmosphere
  • Gases in the atmosphere radiate heat back to the surface

Answers: Options A, D and E

<u>Explanation: </u>

The greenhouse effect, basically a warming effect caused by the greenhouse gases such as Carbon-Di-oxide, Methane, nitrous oxides, water vapour etc. These gases usually trap the heat that Earth Absorbs by the Sun.  

In the day time, the Earth absorbs the energy in the form of heat which is radiated by the Sun. In the evening, the process gets reversed and the Earth starts releasing that heat into the atmosphere.

Now, this heat gets absorbed by this gases before it leaves the Earth's atmosphere and gets trapped there only, resulting in the temperature raise of the Earth's environment.

So, the prime causes of the greenhouse effect remains as the heat radiation from the Sun, the absorption of that heat by the Earth surface and the further absorption of that heat produced by the greenhouse gases that present in the atmosphere.

5 0
3 years ago
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You attach a meter stick to an oak tree, such that the top of the meter stick is 2.27 meters above the ground. later, an acorn f
Alexandra [31]

The acorn was at a height of <u>4.15 m</u> from the ground before it drops.

The acorn takes a time t to fall through a distance h₁, which is the length of the scale. When the acorn reaches the top of the scale, its velocity is u.

Calculate the speed of the acorn at the top of the scale, using the equation of motion,

s=ut+ \frac{1}{2} at^2

Since the acorn falls freely under gravity, its acceleration is equal to the acceleration due to gravity g.

Substitute 2.27 m for s (=h₁), 0.301 s for t and 9.8 m/s² for a (=g).

s=ut+ \frac{1}{2} at^2\\ (2.27 m)=u(0.301s)+\frac{1}{2}(9.8m/s^2)(0.301s)^2\\ u=\frac{1.8261m}{0.301s} =6.067m/s

If the acorn starts from rest and reaches a speed of 6.067 m/s at the top of the scale, it would have fallen a distance h₂ to achieve this speed.

Use the equation of motion,

v^2=u^2+2as

Substitute 6.067 m/s for v, 0 m/s for u, 9.8 m/s² for a (=g) and h₂ for s.

v^2=u^2+2as\\ (6.067m/s)^2=(0m/s)^2+2(9.8m/s^2)h_2\\ h_2=\frac{(6.067m/s)^2}{2(9.8m/s^2)} =1.878 m

The height h above the ground at which the acorn was is given by,

h=h_1+h_2=(2.27 m)+(1.878 m)=4.148 m

The acorn was at a height <u>4.15m</u> from the ground before dropping down.

3 0
3 years ago
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