A projectile has an initial horizontal velocity of 15 meters per second and an initial vertical velocity of 25 meters per second
1 answer:
Answer:
75 m
Explanation:
The horizontal motion of the projectile is a uniform motion with constant speed, since there are no forces acting along the horizontal direction (if we neglect air resistance), so the horizontal acceleration is zero.
The horizontal component of the velocity of the projectile is
and it is constant during the motion;
the total time of flight is
t = 5 s
Therefore, we can apply the formula of the uniform motion to find the horizontal displacement of the projectile:
You might be interested in
Complete Question
The complete question is shown on the first uploaded image
Answer:
Explanation:
From he question we are told that
The first mass is
The second mass is
From the question we can see that at equilibrium the moment about the point where the string holding the bar (where are hanged ) is attached is zero
Therefore we can say that
Making x the subject of the formula
Looking at the diagram we can see that the tension T on the string holding the bar where are hanged is as a result of the masses (
)
Also at equilibrium the moment about the point where the string holding the bar (where () and
are hanged ) is attached is zero
So basically
Making subject
The wavelength of a wave (λ) is given by λ
where c is the wave speed and f is the frequency
where c is the wave speed and f is the frequency