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-BARSIC- [3]
3 years ago
6

Need help with 22 and 24​

Chemistry
2 answers:
Anvisha [2.4K]3 years ago
6 0

Answer:

hey there!, I think get some reference from ramsden chemistry book

choli [55]3 years ago
5 0

Answer:

22:

Formular:

atomic \: mass =  \frac{ \sum(isotopic \: mass \times \%abundance)}{100}  \\

substitute:

atomic \: mass =  \frac{(23.985 \times 78.70) + (24.986 \times 10.13) + (25.983 \times 11.17)}{100}  \\  \\  =  \frac{(1887.620) + (253.108) + (290.230)}{100}  \\  \\  =  \frac{2430.958}{100}  \\  \\ { \boxed{ \boxed{average \: atomic \: mass = 24.3 \: amu}}}

23:

<em>Same</em><em> </em><em>element</em><em> </em><em>is</em><em> </em><em>represented</em><em> </em><em>by</em><em> </em><em>same</em><em> </em><em>number</em><em> </em><em>of</em><em> </em><em>protons</em><em>.</em><em> </em>

Answer:

6 protons. 6 protons

7 neutrons. 8 neutrons

6 electrons. 6 electrons

Note: <u>Atoms</u><u> </u><u>with</u><u> </u><u>same</u><u> </u><u>proton</u><u> </u><u>number</u><u> </u><u>but</u><u> </u><u>different</u><u> </u><u>mass</u><u> </u><u>number</u><u> </u><u>are</u><u> </u><u>called</u><u> </u><u>isotopes</u>

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3 years ago
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Yanka [14]

Answer:

Kp = 7.4727

Explanation:

Let's write the balanced equilibrium reaction:

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Now, if we want to calculate the Kp, we need to write an ICE chart with this reaction, which is the following:

         2NH₃ <-------> N₂ + 3H₂  

I.         4,5                 0        0

C.       -2x                +x     +3x

E.        4,5-2x            x       3x

According to this chart, the Kp expression should be:

Kp = (PH₂)³ * (PN₂) / (PNH₃)²   (1)

The value of x, we already know it because the problem states that the amount of nitrogen gas is 1.1 atm, so replacing this value into (1) we have:

Kp = (3*1.1)³ * (1.1) / (4.5 - (2 * 1.1))²

Kp = 39.5307 / 5.29

<h2>Kp = 7.4727</h2>

Hope this helps

5 0
3 years ago
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Explanation:

6 0
3 years ago
The drawing shows two long rod shaped Structures with horizontal light dark bands
7nadin3 [17]

Answer:

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There are currently three known types of photoreceptor cells in mammalian eyes: rods, cones, and photosensitive retinal ganglion cells. The two classic photoreceptor cells are rods and cones, each contributing information used by the visual system to form a representation of the visual world, sight. The rods are narrower than the cones and distributed differently across the retina, but the chemical process in each that supports phototransduction is similar. A third class of mammalian photoreceptor cell was discovered during the 1990s: the photosensitive ganglion cells. These cells do not contribute to sight directly, but are thought to support circadian rhythms and pupillary reflex.

Explanation:

4 0
3 years ago
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nadezda [96]

Answer:

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8 0
2 years ago
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