<h3><u>Answer</u> :</h3>
![\bigstar\:\boxed{\bf{\purple{x^{\frac{m}{n}}}=\orange{(\sqrt[n]{x})^m}}}](https://tex.z-dn.net/?f=%5Cbigstar%5C%3A%5Cboxed%7B%5Cbf%7B%5Cpurple%7Bx%5E%7B%5Cfrac%7Bm%7D%7Bn%7D%7D%7D%3D%5Corange%7B%28%5Csqrt%5Bn%5D%7Bx%7D%29%5Em%7D%7D%7D)
Let's solve !
![:\implies\sf\:(\sqrt[2]{25})^3](https://tex.z-dn.net/?f=%3A%5Cimplies%5Csf%5C%3A%28%5Csqrt%5B2%5D%7B25%7D%29%5E3)
<u>Hence, Oprion-D is correct</u> !
Answer:
Perpendicular H = 5.244 m (Approx)
Step-by-step explanation:
Given:
Hypotenuse = 9.4 m
Base = 7.8 m
Find:
Perpendicular H
Computation:
Perpendicular H = √Hypotenuse² - Base²
Perpendicular H = √9.4² - 7.8²
Perpendicular H = √Hypotenuse² - Base²
Perpendicular H = 5.244 m (Approx)
This question was posted almost a week ago, and I am not sure if you still need the answer, but I'll explain it.
The total number of all of the shapes were placed in the bag are equal to 100. The number comes from adding 32+20+48=100.
This is our total number and will be the denominator.
There are a total of 32 cards which have a hexagon, this number will be our numerator.
So far we have 32/100 , but this is not simplest form.
Next to reduce the fraction, the GCF must be found.
32: 1, 2, 4, 8, 32
100: :
