Ethane consists of 6C−H bonds and 1C−C bond. Total number of bonds is 7. Each bond is made up of two electrons
<h2>
<em>#</em><em>L</em><em>E</em><em>T</em><em>S</em><em> </em><em>STUDY</em></h2>
<em>#</em><em>B</em><em>R</em><em>A</em><em>I</em><em>N</em><em>L</em><em>E</em><em>S</em><em>T</em><em> </em><em>LOVE❣️</em>
Answer:
upward (F=ma if f is up a is up)
Oxidation state of I is (-1) and for CO it is zero. Let's assume that the oxidation state of Fe in Fe(CO)₄I₂<span> (s) is x. For whole compound, the charge is zero.
Sum of oxidation numbers in all elements = Charge of the compound.
Here we have 1Fe , 4CO and 2I
hence we can find the oxidation state as;
x + 4*0 + 2*(-1) = 0
x + 0 - 2 = 0
x = +2
Hence the oxidation state of Fe in product </span>Fe(CO)₄I₂ (s) is +2.
Same as we can find the oxidation state (y) of Fe in Fe(CO)₅(s).
y + 5*0 = 0
y = 0
Since oxidation state of Fe increased from 0 to +2, the oxidized element is Fe in the given reaction.
Zn = 28.15%
Cl = 30.53%
O = 41.32%
<h3>Further explanation</h3>
Given
Zn(CIO3)2 compound
Required
The % composition
Solution
Ar Zn = 65.38
Ar Cl = 35,453
Ar O = 15,999
MW Zn(CIO3)2 = 232.3
Zn = 65,38/232.3 x 100% = 28.15%
Cl = (2 x 35.453) / 232.3 x 100% = 30.53%
O = (6 x 15.999) / 232.3 x 100% = 41.32%
<u>Answer:</u> The correct option is d) 460 kJ
<u>Explanation:</u>
We are given:
Content of fat in energy drink = 2.0 g
Content of protein in energy drink = 6.0 g
Content of carbohydrate in energy drink = 16.3 g
Also,
The fuel value of fat = 38 kJ/g
The fuel value of protein = 17 kJ/g
The fuel value of carbohydrate = 17 kJ/g
So, the fuel value of the energy drink will be:
Total fuel value = 
Total fuel value = ![[76+102+277]=460kJ](https://tex.z-dn.net/?f=%5B76%2B102%2B277%5D%3D460kJ)
Hence, the correct option is d) 460 kJ
